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anonymous

  • one year ago

Trigonometric expression help (look in comments)

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  1. anonymous
    • one year ago
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    \[\frac{ \tan 15 ° }{ 1 - \tan^215 ° }\] I know there's a formula but the answer in the back of my textbook gives me the solution: |dw:1443639097573:dw| How do you get the 1/2 and then the nominator is 2tan 15 °?

  2. anonymous
    • one year ago
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    the formula for tangent in this case (where there is \[\tan 2\alpha \] ) is \[ \frac{ 2\tan \alpha }{ 1 - \tan^2 \alpha }\]

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