A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
solve sqrt(y)dx+(1+x)dy=0
anonymous
 one year ago
solve sqrt(y)dx+(1+x)dy=0

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sqrt(y)/dy=(1+x)/dx

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{y} dx +(1+x)dy=0\] You can start off by dividing both sides by "dx": \[\frac{ \sqrt{y} dx +(1+x)dy }{ dx }=\frac{ 0 }{ dx }\] \[\sqrt{y}\frac{ dx }{ dx }+\frac{ dy }{ dx }(1+x)=0\] \[\frac{ \sqrt{y} }{ dy }=\frac{ (1+x) }{ dx }\] Now, integrating both sides: \[\int\limits \sqrt{y} \frac{ 1 }{ dy }= \int\limits (1+x)\frac{ 1 }{ dx }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how can i integrate that

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\large\color{black}{ \displaystyle \sqrt{y}dx+(1+x)dy=0 }\) \(\large\color{black}{ \displaystyle \sqrt{y}dx=(1+x)dy }\) \(\large\color{black}{ \displaystyle \sqrt{y}\frac{dx}{dy}=(1+x) }\) \(\large\color{black}{ \displaystyle \frac{1}{(1+x)}\frac{dx}{dy}= \frac{1}{\sqrt{y}}}\) integrate both sides with respect to y.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0left side is same just no dx/dy right

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1when you integrate the left side with respect to y, the *dy*s are going to cancel.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1dw:1443641216073:dw

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1hen solve for y. Algebraic task...
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.