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anonymous
 one year ago
medalI just need help figuring out this question not just the answer please
The table below represents the velocity of a car as a function of time:
Time Velocity
(hour) (miles/hours)
x y
0 50
1 52
2 54
3 56
Part A: What is the yintercept of the function, and what does this tell you about the car?
Part B: Calculate the average rate of change of the function represented by the table between x = 1 to x = 3 hours, and tell what the average rate represents.
Part C: What would be the domain of the function if the velocity of the car was measured until it reached 60
anonymous
 one year ago
medalI just need help figuring out this question not just the answer please The table below represents the velocity of a car as a function of time: Time Velocity (hour) (miles/hours) x y 0 50 1 52 2 54 3 56 Part A: What is the yintercept of the function, and what does this tell you about the car? Part B: Calculate the average rate of change of the function represented by the table between x = 1 to x = 3 hours, and tell what the average rate represents. Part C: What would be the domain of the function if the velocity of the car was measured until it reached 60

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Could you please help me if you can @Nnesha or @whpalmer4 or if you know someone you can tag to help

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2What is the definition of the \(y\)intercept?

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2So, what is the definition of the \(y\)intercept?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it is the point on a graph when the x is equalled to 0....?

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2Well, it's the value of \(y\) at the point on the graph where \(x=0\). Also the point where the graph crosses the \(y\)axis.

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2So if we graphed the data in the table, would the \(x\)axis be time, or velocity?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x wold be time because the velocity would be y

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2good. so now you can tell me the answer to part A...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so when x is 0 y is 50

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2Yes. And as \(x\) represents time, that's the initial velocity of the car, right? 50 miles/hour

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes so all i have to write would be.... the y intercept would be 50 if x is 0 im not sure how to word it

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2How about "the yintercept of the function is 50 miles/hour"?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok ..... :) but it also says what does this tell you about the car? i dont know how to figure that out or does that answer the entire question ? @whpalmer4

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2If you look back a few responses, I think you will find that I made a comment about what that represents...

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2The data in the table shows the car starting at 50 mph and going faster with each passing hour, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes by 2 miles per hour

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2no, but close: it changes by 2 miles per hour per hour...

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2no, "you're right" :)

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2On to part B! How do you find the average rate of change?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0average rate of change for an function f(x) is intervals from a to b so the formula is f(b)f(a) over ba

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2okay, do you understand how to translate your table values into a,b,f()?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@whpalmer4 i was reading my notes from class would F(a) be x and f (b) be y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so would it be from the table 5250 over 10 ??? not sure

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2Well, \(x\) takes on the values of \(a\) and \(b\) and \(y = f(x)\) So at \(x=1 \text{ hour}\) we have \(a = x = 1\text{ hour}\) and \(f(1) = \) what?

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2Yes. so \(a = 1\) and \(f(a) = 52\) Now how about \(b\) and \(f(b)\)?

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2why does b = 2? and f(b) is the value of the function at x=b=2, which doesn't appear to be 2 when I read the table... Here's the initial problem again: Part B: Calculate the average rate of change of the function represented by the table between x = 1 to x = 3 hours, and tell what the average rate represents. ^^^^^^^^^

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2well, my attempt to underline "\(x=3\)" didn't work so well!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh So b =3 and f(b)=56

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2yes! we are trying to find the average rate of change over that 2 hour span, so \(a\) is the value of \(x\) or \(t\) at the start, and \(b\) is the value of \(x\) or \(t\) at the end, and \(f(a)\) and \(f(b)\) are the values from the table.

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2So our average rate of change between \(a\) and \(b\) is as your formula states: \[\text{avg rate of change} = \frac{f(b)f(a)}{ba}\]

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2Can you plug in the values?

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2Okay, if you are going to write equations on one line like that, you MUST use parentheses appropriately to show what isn't being shown by position! what you wrote is actually equal to this: \[56  \frac{52}{3}  1 = \frac{4}{2}\] I know that isn't what you meant. (5652)/(31) = 4/2 would unambiguously convey the intended meaning

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2What will the units for your answer be? miles? miles per hour? something else?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ok thanks for that tip and my units would be miles per hour or miles/hour

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so ithe change of rate would be 2 miles per hour

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2right number, wrong unit \[\frac{56 \text{ miles/hr}  52 \text{ miles/hr}}{3\text{ hr}  1\text{ hr}} = \frac{4\text{ miles/hr}}{2\text{ hr}} = 2 \text{miles/hr}^2\] \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you explain why is it hr^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I dont know how to get the little 2 sorry

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2right? if we continue accelerating at this rate, for every hour that passes, we will increase our speed by 2 miles/hour. If we accelerate for 10 hours, we will add \[10\text{ hours}*2\frac{\text{ miles}}{\text{hour*hour}} = 10\cancel{\text{ hours}}*2\frac{\text{ miles}}{\text{hour}*\cancel{\text{hour}}} \] \[= 20 \frac{\text{ miles}}{\text{hour}}\] to our speed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh yes ........ :0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks for explaining it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my mom says we have to go to church can i see if your on later to finish :)

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2the way it "builds up" in physics terminology: \[x = v t\]distance = speed * time \[v = a t\]velocity = acceleration * time

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.2Sure, say hi to the big guy for me :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol i will thank you so much
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