## hpfan101 one year ago Find an equation of the tangent line to the curve at the given point y=sqrt{x} (1,1)

1. hpfan101

$y=\sqrt(x)$

2. hpfan101

Given point (1,1).

3. freckles

First step differentiate

4. freckles

We do this because we know f'(1) will give us the slope of the line that is tangent to the curve y=sqrt(x) at (1,1)

5. freckles

point slope form for a line that contains the point (a,b) is y-b=m(x-a) where m is the slope... so here you will have: y-f(1)=f'(1)(x-1) where f(1)=sqrt(1)=1 <--this was actually given so you have y-1=f'(1)(x-1) only work for you to do is to find f'(1) and replace f'(1) here

6. hpfan101

Alright, thank you very much!

7. freckles

np