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hpfan101
 one year ago
Find an equation of the tangent line to the curve at the given point y=sqrt{x} (1,1)
hpfan101
 one year ago
Find an equation of the tangent line to the curve at the given point y=sqrt{x} (1,1)

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freckles
 one year ago
Best ResponseYou've already chosen the best response.1First step differentiate

freckles
 one year ago
Best ResponseYou've already chosen the best response.1We do this because we know f'(1) will give us the slope of the line that is tangent to the curve y=sqrt(x) at (1,1)

freckles
 one year ago
Best ResponseYou've already chosen the best response.1point slope form for a line that contains the point (a,b) is yb=m(xa) where m is the slope... so here you will have: yf(1)=f'(1)(x1) where f(1)=sqrt(1)=1 <this was actually given so you have y1=f'(1)(x1) only work for you to do is to find f'(1) and replace f'(1) here

hpfan101
 one year ago
Best ResponseYou've already chosen the best response.0Alright, thank you very much!
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