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haleyelizabeth2017
 one year ago
Find the inverse of f(x). (there are two)
haleyelizabeth2017
 one year ago
Find the inverse of f(x). (there are two)

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haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0\[f(x)=4x^2+1\]

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Don't I switch f(x) and x to begin with?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2f(x) is same as y so we can rewrite this as \[\huge\rm y=4x^2+1\] to find inverse switch x and y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf f(x)={\color{blue}{ y}}=4{\color{brown}{ x}}^2+1\qquad inverse\implies {\color{brown}{ x}}=4{\color{blue}{ y}}^2+1\impliedby f^{1}(x)\) yes

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0I got: \[y=\sqrt{\frac {x1}{4}}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2hmm \[\huge\rm \color{ReD}{x}=4\color{blue}{y}^2+1\] divide by 4 \[\frac{ x1 }{ 4 } \] is same as \[\huge\rm \frac{ x }{ 4 } \frac{ 1 }{ 4 }\] first divide the sign and then take square root and remember when we take square root we should get 2 solutions \[\sqrt{x^2} = \pm x\]

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0wait, what? Sorry, you lost me there lol

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{ x }{ 4 }\frac{ 1 }{ 4 } = \frac{ x }{ 4 }+\frac{ 1 }{ 4 }\] 1 divided by 4 = positive 1/4

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2hint \[\sqrt{\frac{ a }{ b }}=\frac{ \sqrt{a} }{ \sqrt{b} }\]

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0So, \[\frac{\sqrt{x+1}}{2}\]?

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Thank you :)

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Is that all?

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Awesome! :) And it is also a function, correct?
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