can someone please help me with a problem

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can someone please help me with a problem

Mathematics
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Create a table of values for a linear function. A drone is in the distance, flying upward in a straight line. It intersects the rainbow at two points. Choose the points where your drone intersects the parabola and create a table of at least four values for the function. Remember to include the two points of intersection in your table.

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i dont really get this
can i get a example of a table of values for a linear function
ahemm , it helps if you had named the "picture" with a pdf extension anyway
i dont know how to do that
so... you have a parabola and you're meant to make a LINEar function/equation graph touch it at two points notice the parabola, pick any two points you wish to touch it at first :)
what you're asked, is pretty much|dw:1443657510281:dw|
so 0,36
ok... 0,36 is one point and the other point?
6,0
kinda cheap, since those are labeled already =) but anyhow, let us use that so.... what's the equation of that line, that crosses the points of (0,36) and (0,6) ?
The equation for this parabola is y = -x2 + 36. this the equation they give me
ok... how about the line with those points at 0,36) and (6,0) ?
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 0}}\quad ,&{\color{blue}{ b}})\quad % (c,d) &({\color{red}{ 6}}\quad ,&{\color{blue}{ 0}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ % point-slope intercept y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values}\\ \qquad \uparrow\\ \textit{point-slope form}\) to get the line, get the slope, and then plug in the values of \(x_1, y_1\ and\ the\ slope\)
wooop missing a number there =) \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 0}}\quad ,&{\color{blue}{ 36}})\quad % (c,d) &({\color{red}{ 6}}\quad ,&{\color{blue}{ 0}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ % point-slope intercept y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values}\\ \qquad \uparrow\\ \textit{point-slope form}\)
once you have the equation you can use that, to make the table of values you're only asked for 4 values anyhow and to include those (0,36) and (6,0) so you just need two other values and you can get those from the equation
question do i get 2 other point from the graph or i make my own
well... has to be from the graph because the two points of (0,36) and (6,0) are ON the line and the other two points have to also be ON the same line since the table of values is for the line
for example... what would you get for the slope at \(\begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 0}}\quad ,&{\color{blue}{ 36}})\quad % (c,d) &({\color{red}{ 6}}\quad ,&{\color{blue}{ 0}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\) ?
|dw:1443581429201:dw|
do i put it someting like this
yes
well... it should be |dw:1443658208506:dw|
so... what slope would you get from \(\begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 0}}\quad ,&{\color{blue}{ 36}})\quad % (c,d) &({\color{red}{ 6}}\quad ,&{\color{blue}{ 0}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} ?\)
|dw:1443581611578:dw|
@jdoe0001 is that good

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