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lovelycharm

  • one year ago

can someone please help me with a problem

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  1. vikstar2.0
    • one year ago
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    whats your problem

  2. lovelycharm
    • one year ago
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  3. lovelycharm
    • one year ago
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    Create a table of values for a linear function. A drone is in the distance, flying upward in a straight line. It intersects the rainbow at two points. Choose the points where your drone intersects the parabola and create a table of at least four values for the function. Remember to include the two points of intersection in your table.

  4. lovelycharm
    • one year ago
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    i dont really get this

  5. lovelycharm
    • one year ago
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    can i get a example of a table of values for a linear function

  6. jdoe0001
    • one year ago
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    ahemm , it helps if you had named the "picture" with a pdf extension anyway

  7. lovelycharm
    • one year ago
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    i dont know how to do that

  8. jdoe0001
    • one year ago
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    so... you have a parabola and you're meant to make a LINEar function/equation graph touch it at two points notice the parabola, pick any two points you wish to touch it at first :)

  9. jdoe0001
    • one year ago
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    what you're asked, is pretty much|dw:1443657510281:dw|

  10. lovelycharm
    • one year ago
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    so 0,36

  11. jdoe0001
    • one year ago
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    ok... 0,36 is one point and the other point?

  12. lovelycharm
    • one year ago
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    6,0

  13. jdoe0001
    • one year ago
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    kinda cheap, since those are labeled already =) but anyhow, let us use that so.... what's the equation of that line, that crosses the points of (0,36) and (0,6) ?

  14. lovelycharm
    • one year ago
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    The equation for this parabola is y = -x2 + 36. this the equation they give me

  15. jdoe0001
    • one year ago
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    ok... how about the line with those points at 0,36) and (6,0) ?

  16. jdoe0001
    • one year ago
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    \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 0}}\quad ,&{\color{blue}{ b}})\quad % (c,d) &({\color{red}{ 6}}\quad ,&{\color{blue}{ 0}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ % point-slope intercept y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values}\\ \qquad \uparrow\\ \textit{point-slope form}\) to get the line, get the slope, and then plug in the values of \(x_1, y_1\ and\ the\ slope\)

  17. jdoe0001
    • one year ago
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    wooop missing a number there =) \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 0}}\quad ,&{\color{blue}{ 36}})\quad % (c,d) &({\color{red}{ 6}}\quad ,&{\color{blue}{ 0}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ % point-slope intercept y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values}\\ \qquad \uparrow\\ \textit{point-slope form}\)

  18. jdoe0001
    • one year ago
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    once you have the equation you can use that, to make the table of values you're only asked for 4 values anyhow and to include those (0,36) and (6,0) so you just need two other values and you can get those from the equation

  19. lovelycharm
    • one year ago
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    question do i get 2 other point from the graph or i make my own

  20. jdoe0001
    • one year ago
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    well... has to be from the graph because the two points of (0,36) and (6,0) are ON the line and the other two points have to also be ON the same line since the table of values is for the line

  21. jdoe0001
    • one year ago
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    for example... what would you get for the slope at \(\begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 0}}\quad ,&{\color{blue}{ 36}})\quad % (c,d) &({\color{red}{ 6}}\quad ,&{\color{blue}{ 0}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\) ?

  22. lovelycharm
    • one year ago
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    |dw:1443581429201:dw|

  23. lovelycharm
    • one year ago
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    do i put it someting like this

  24. jdoe0001
    • one year ago
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    yes

  25. jdoe0001
    • one year ago
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    well... it should be |dw:1443658208506:dw|

  26. jdoe0001
    • one year ago
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    so... what slope would you get from \(\begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 0}}\quad ,&{\color{blue}{ 36}})\quad % (c,d) &({\color{red}{ 6}}\quad ,&{\color{blue}{ 0}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} ?\)

  27. lovelycharm
    • one year ago
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    |dw:1443581611578:dw|

  28. lovelycharm
    • one year ago
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    @jdoe0001 is that good

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