lovelycharm
  • lovelycharm
can someone please help me with a problem
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
vikstar2.0
  • vikstar2.0
whats your problem
lovelycharm
  • lovelycharm
1 Attachment
lovelycharm
  • lovelycharm
Create a table of values for a linear function. A drone is in the distance, flying upward in a straight line. It intersects the rainbow at two points. Choose the points where your drone intersects the parabola and create a table of at least four values for the function. Remember to include the two points of intersection in your table.

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lovelycharm
  • lovelycharm
i dont really get this
lovelycharm
  • lovelycharm
can i get a example of a table of values for a linear function
jdoe0001
  • jdoe0001
ahemm , it helps if you had named the "picture" with a pdf extension anyway
lovelycharm
  • lovelycharm
i dont know how to do that
jdoe0001
  • jdoe0001
so... you have a parabola and you're meant to make a LINEar function/equation graph touch it at two points notice the parabola, pick any two points you wish to touch it at first :)
jdoe0001
  • jdoe0001
what you're asked, is pretty much|dw:1443657510281:dw|
lovelycharm
  • lovelycharm
so 0,36
jdoe0001
  • jdoe0001
ok... 0,36 is one point and the other point?
lovelycharm
  • lovelycharm
6,0
jdoe0001
  • jdoe0001
kinda cheap, since those are labeled already =) but anyhow, let us use that so.... what's the equation of that line, that crosses the points of (0,36) and (0,6) ?
lovelycharm
  • lovelycharm
The equation for this parabola is y = -x2 + 36. this the equation they give me
jdoe0001
  • jdoe0001
ok... how about the line with those points at 0,36) and (6,0) ?
jdoe0001
  • jdoe0001
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 0}}\quad ,&{\color{blue}{ b}})\quad % (c,d) &({\color{red}{ 6}}\quad ,&{\color{blue}{ 0}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ % point-slope intercept y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values}\\ \qquad \uparrow\\ \textit{point-slope form}\) to get the line, get the slope, and then plug in the values of \(x_1, y_1\ and\ the\ slope\)
jdoe0001
  • jdoe0001
wooop missing a number there =) \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 0}}\quad ,&{\color{blue}{ 36}})\quad % (c,d) &({\color{red}{ 6}}\quad ,&{\color{blue}{ 0}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ % point-slope intercept y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values}\\ \qquad \uparrow\\ \textit{point-slope form}\)
jdoe0001
  • jdoe0001
once you have the equation you can use that, to make the table of values you're only asked for 4 values anyhow and to include those (0,36) and (6,0) so you just need two other values and you can get those from the equation
lovelycharm
  • lovelycharm
question do i get 2 other point from the graph or i make my own
jdoe0001
  • jdoe0001
well... has to be from the graph because the two points of (0,36) and (6,0) are ON the line and the other two points have to also be ON the same line since the table of values is for the line
jdoe0001
  • jdoe0001
for example... what would you get for the slope at \(\begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 0}}\quad ,&{\color{blue}{ 36}})\quad % (c,d) &({\color{red}{ 6}}\quad ,&{\color{blue}{ 0}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\) ?
lovelycharm
  • lovelycharm
|dw:1443581429201:dw|
lovelycharm
  • lovelycharm
do i put it someting like this
jdoe0001
  • jdoe0001
yes
jdoe0001
  • jdoe0001
well... it should be |dw:1443658208506:dw|
jdoe0001
  • jdoe0001
so... what slope would you get from \(\begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 0}}\quad ,&{\color{blue}{ 36}})\quad % (c,d) &({\color{red}{ 6}}\quad ,&{\color{blue}{ 0}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} ?\)
lovelycharm
  • lovelycharm
|dw:1443581611578:dw|
lovelycharm
  • lovelycharm
@jdoe0001 is that good

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