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what are the equations

\[\frac{ x }{ 4 } - \frac{ y }{ 3 } = 1 \]

thats it or is there more

there is more

just wait im typing the equation

\[\frac{ 5 }{ x } - \frac{ 2 }{ y } = 7\]

So is it:
a)the first one
b)the second one
c)or both

i think it is both

but most likely the first one

i need the work though

Anybody who can help me????

how am i supposed to show the work?

any equation in the form of y=mx+b is linear

i thought it was supposed to be ax+by=c

anyways could u pls explain

Try re writing both in linear form.

For the first one, I think it is 3x-4y=12, but I'm still not that sure how I got 12.

.Please show the work you did to get that.

Aw man, he's offline. :(

Is there a way you can post the questions and options in one post?

I do not know. Do you want the options?

The approach you took is not "algebraic" and would be considered an incorrect approach.

Oh sorry could you please help me to do it the correct way?

You don't cross multiply The difference of two fractions.

Oh ok.

Multiply both sides of the equation by the LCD

You mean the Least Common Denominator?

Exactly.

Ok let me try. Don't leave, please.

But there are 2 fractions on one side of the equation, so how will I find the LCD?

I'm sorry for being so dumb.

Your talking about the first equation, right?

Correct.

Ok so I should multiply 12 with both the fractions and 1, right?

Correct

Ok.

Don't forget to cross cancel where possible.

So:
12x/4 - 12y/3 = 12
3x - 4y = 12

Correct

So you know the first equation is linear since it has the general linear form.

OK NOW I GET IT! Isn't 3x - 4y = 12 a linear equation in standard form, which is
ax - by = c

Now try writing the second equation In the same form.

Ok just wait. Please don't leave.

So 10 is the LCD for the second equation, right?

Tell me what is in the denominators of the fractions of the Second equation?

x and y.

Explain how 10 Can be the LCD of x and y.

Or am I wrong?

Actually, there IS an LCD for denominators x and y.

Is it xy

You find it the same way you found the LCD of 3 and 4

Correct

Yay! But the second equation isn't a linear equation, right?

You have to SHOW that it isn't

I don't actually know how to do that.

Please help me out.

Try to write it in linear form. You already found the LCD. Remember what to do afterwards?

OH YEAH! Just give a minute. I'll solve it out. Just stay there.

So:
5xy/1x - 3xy/1y = 7xy

Cross cancel

What are those?

Factors of one that allow you to Simplify expressions.

Oh ok.

Cross cancel

So:
5xy - 3xy = 7xy

You have good intention but that is not the correct Simplification.

:(

How do I do that?

What does x/x =1 mean to you?

1/1=1

Well that would imply that x=1 but x is a variable

I'm confused.

The factors together Cancel to get 1 but a factor by itself does not equal one.

Oh ok but I don't know where this going.

For example, 7/7 =1 but 7 ≠1

Ok.

So you should have ended up With:

5y-3x = 7xy

oh ok

Which can also be written as -3x + 5y = 7xy

so it is not a linear equation

But it is NOT Linear because 7xy is clearly not a constant,

So, yes, correct, not linear.

ok

yw