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anonymous
 one year ago
help pls im begging you all
anonymous
 one year ago
help pls im begging you all

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pooja195
 one year ago
Best ResponseYou've already chosen the best response.0It helps i you actually asked your question.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73 @whpalmer4 @Zale101 @thomaster

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1@saylilbaby are you here now?

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1Okay, let's look at the first one. Are you able to factor the numerator and denominator?

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{n^411n^2+30}{n^47n^2+10}\]

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1looking at the numerator, \(n^411n^2+30\) what are two numbers which when multiplied give you \(30\), but when added give you \(11\)? Hopefully it is obvious that both must be negative numbers.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is it C @whpalmer4 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or A im confused @whpalmer4

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1Let's work through the problem together, and you should be certain of your answer by the time we are done.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i already worked thru i just needto state the restriction @whpalmer4

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1Ok, didn't want to assume that...but it makes life easier :) So, let's look at the factored denominator of the original expression: \[n^47n^2+10 = (n^25)(n^22)\]Agreed?

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1When we find the restrictions, we have to do so on the unsimplified version, because we still have a "hole" in the function at those spots where we simplified away a term in the denominator. That means our restrictions on \(n\) here are located at all values of \(n\) where \[n^25=0\]and\[n^22=0\] Any value of \(n\) that makes either of those true will cause a division by \(0\) in the original expression.

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1We can see that A is not the right answer, because the restrictions it imposes are \(n\ne5\) and \(n\ne2\), but those values do not cause the original denominator to be equal to \(0\). \[(5^25)(5^22) = 460\]\[(2^25)(2^22) = 2\]

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1D is also not a correct answer for the same reason. \[(5^25)(5^22) = 460\]\[(2)^25)((2)^22) = 2\]

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1B has the wrong fraction, so our hopes are left with C. Let's check it! \[n\ne \pm \sqrt{5}\]\[n\ne\pm\sqrt{2}\] If we evaluate the original denominator at \(n=\sqrt{5}\) \[(\sqrt{5}^25)(\sqrt{5}^22) = (55)(52)= 0 \] If we evaluate the original denominator at \(n=\sqrt{5}\) \[((\sqrt{5})^25)((\sqrt{5})^22) = (55)(52)=0 \] So far, so good. Now trying \(n=\pm\sqrt{2}\) \[(\sqrt{2}^25)(\sqrt{2}^22) = (25)(22) = 0\] \[((\sqrt{2})^25)((\sqrt{2})^2) = (25)(22) = 0\] Those are all good, so C is our answer.

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1To find the restrictions, factor the initial denominator. Set each product term \(=0\) and find all the values which satisfy that. The list of all of such values for all of the terms is the set of restrictions on the expression.
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