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solve for x ??
divide by (x-3) 9and that gives you x-3=0 solution right of, leaving you with x+2=x-3 which is ....
alright (x-3)^2 is same as (x-3)(x-3 )\[\huge\rm (x+2)(x-3)=(x-3)(x-3)\] you can divide both sides by x-3 and then solve for x
yes, but again as I noted, when you divide by x-3, you will have that x-3=0 is also a solution.
(to check 0=0)
You don't have to divide by x-3 By observation, x+2=x-3
And solving for x doesn't seem to yield a solution.
Im confused ppl.. walk me through it?
that is from dividing by x-3, and I am sure you would get that solution if you were to just solve it in another way.
Xes x=3 is a solution but you don't need to divide anything to get that
ahh i see. you can distribute the parentheses FOL it (x-3)(x-3) and (x-3)(x+2)
foil* familiar with the foil method ?
distribute and then solve for x u will get the correct answer.
Nope, you don't need foil EITHER
That is the correct solution.