## clamin one year ago PLEASE HELP!!! MEDAL!!! I Use synthetic division to solve. is this right??

1. clamin

|dw:1443661956244:dw| did i do this righ??

2. zepdrix

No that's not quite right. If you want to do $$\large\rm \frac{-32}{3}+6$$ then you need to get a common denominator before adding. This seems like a really difficult way to do synthetic though... What's the problem look like? Can't we get rid of those fractions maybe? :o

3. clamin

i dont know how to find common denominator.@zepdrix

4. kva1992

clamin what is the original problem?

5. clamin

|dw:1443663192218:dw| @kva1992

6. kva1992

alright so your set up is right only thing is the denominator zep was referring to so if yoru adding -32/3 + 6 it would be converted to -32/3+18/3 then you would subtract and what not

7. kva1992

does that make sense and do you see what i did?

8. kva1992

in order to subtract that problem you must convert it to an improper fraction

9. kva1992

the method you chose to solve it is correct you just didnt subtract and add properly

10. kva1992

hopefully that helped @clamin

11. clamin

where did you get that 18/3?? @kva1992

12. kva1992

change the 6 into a improper fraction since your using 3 as the denominator it would become 18/3

13. kva1992

change the 6 into a improper fraction since your using 3 as the denominator it would become 18/3

14. freckles

I like @zepdrix 's idea of getting rid of the nasty fractions in the top polynomial and then dividing using synthetic route

15. freckles

$\frac{-6p^4-32p^3-50p^2-8p+33}{3(2p+6)} =\frac{-6p^4-32p^3-50p^2-8p+33}{6p+18}$

16. freckles

now divide

17. kva1992

that works as well