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@pooja195 @SolomonZelman @zepdrix Halp
Consider one coordinate at a time. Take the x-coordinates, for example. Endpoint U has an x-coordinate of 3 and the midpoint has an x-coordinate of 5. The x-coordinate of endpoint V will be the same horizontal distance away from the midpoint.
Then what x-coordinate would be 2 units away from 5, and in the opposite direction from endpoint U?
Very good. Now do the same thing with the y-coordinates. Endpoint U has y-coordinate of 5, midpoint has y-coordinate of -11. Endpoint V has a y-coordinate the same vertical distance away from the midpoint in the direction opposite to endpoint U.
Sorry, I'm confused, same vertical distance away from he midpoint and the endpoint U?
OK. How many units do you need to move to go from 5 to -11?
Great. So keep going another 16 units and where do you end up?
No. Maybe the explanation is not clear. In the vertical direction (specified by the y-coordinates) you moved from a y-coordinate of 5 to a y-coordinate of -11 - a vertical distance of 16 units (technically -16 units). Keep moving another -16 units from -11 and where do you end up?
Correct. Now you have your x- and y-coordinates for the other endpoint.
No. (7, -27)
Oh yeah sorry, forgot the negative--thankyou so much! This made a lot of sense >^-^<