anonymous
  • anonymous
Solve this equation for x. Round your answer to the nearest hundredth. 1= ln(x+8) Use the property z=a^logaZ
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
applying that property, you know that: \(e^{\ln x} = x\) .. for your question, change the bases into e on both sides, so it will look like this: \(\sf \large e^1= e^{ln(x+8)}\) now simplify this using the property
anonymous
  • anonymous
Im still confused...could you explain the process??
anonymous
  • anonymous
if \(\ln(\text{whatever})=1\) then \(\text{whatever}=e\)

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anonymous
  • anonymous
How do i go about finding the answer? I dont understand
anonymous
  • anonymous
Would it be 2??
owlet
  • owlet
What is e^1?
anonymous
  • anonymous
I dont know what e^1 is
owlet
  • owlet
then using the rule, what is e^ln(x+8) simplify to? it is like z=a^log a z, a= e z= x+8 , therefore, e^ln(x+8) is equal to?
owlet
  • owlet
any number raised by one will be equal to the number itself., so e^1 =e
anonymous
  • anonymous
I still dont understand how to find the answer.
owlet
  • owlet
simplify the equation first before you can find the value of x
anonymous
  • anonymous
Ok
owlet
  • owlet
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