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anonymous

  • one year ago

Solve this equation for x. Round your answer to the nearest hundredth. 1= ln(x+8) Use the property z=a^logaZ

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  1. anonymous
    • one year ago
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    applying that property, you know that: \(e^{\ln x} = x\) .. for your question, change the bases into e on both sides, so it will look like this: \(\sf \large e^1= e^{ln(x+8)}\) now simplify this using the property

  2. anonymous
    • one year ago
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    Im still confused...could you explain the process??

  3. anonymous
    • one year ago
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    if \(\ln(\text{whatever})=1\) then \(\text{whatever}=e\)

  4. anonymous
    • one year ago
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    How do i go about finding the answer? I dont understand

  5. anonymous
    • one year ago
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    Would it be 2??

  6. owlet
    • one year ago
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    What is e^1?

  7. anonymous
    • one year ago
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    I dont know what e^1 is

  8. owlet
    • one year ago
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    then using the rule, what is e^ln(x+8) simplify to? it is like z=a^log a z, a= e z= x+8 , therefore, e^ln(x+8) is equal to?

  9. owlet
    • one year ago
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    any number raised by one will be equal to the number itself., so e^1 =e

  10. anonymous
    • one year ago
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    I still dont understand how to find the answer.

  11. owlet
    • one year ago
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    simplify the equation first before you can find the value of x

  12. anonymous
    • one year ago
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    Ok

  13. owlet
    • one year ago
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    |dw:1443664397951:dw|

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spraguer (Moderator)
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