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Theloshua
 one year ago
(x + 2)(3x) = (x + 2)(6)
Theloshua
 one year ago
(x + 2)(3x) = (x + 2)(6)

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Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1distribute on both sides

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1good, now subtract 6x from each side

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1good, now divide both sides by 3

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1almost, don't forget x = 2 as well x = 2 and x = 2

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1when we solve x^2 = A, we must take into account the positive and negative square roots

Theloshua
 one year ago
Best ResponseYou've already chosen the best response.0but if its squared doesnt it turn positive?

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1right, that's precisely why we need to take both positive and negative roots

Theloshua
 one year ago
Best ResponseYou've already chosen the best response.0can you type it out so i can see?

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1we got down to x^2 = 4, right?

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1you found x = 2, which works when we substitute back into the equation x^2 = 4 2^2 = 4

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1notice what happens when we let x = 2 instead x^2 = 4 (2)^2 = 4 4 = 4 therefore, x = 2 is also a solution.

Theloshua
 one year ago
Best ResponseYou've already chosen the best response.0ohhhhh..... but is that how I figure it out in every situation, or is there a way so it becomes part of the routine of solving the problem?

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1in general: dw:1443665411909:dw this is a tricky concept

Theloshua
 one year ago
Best ResponseYou've already chosen the best response.0XD okay, okay, I get you *sticks out tongue at you*
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