anonymous
  • anonymous
Find the exact value of tan(M).
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
do we know anything at all about \(M\)?
anonymous
  • anonymous
anonymous
  • anonymous
\[\tan(M)=\frac{\text{opposite}}{\text{adjacent}}\]

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More answers

anonymous
  • anonymous
|dw:1443665613699:dw|
anonymous
  • anonymous
oh 5/12
anonymous
  • anonymous
yup
anonymous
  • anonymous
can I ask more?
anonymous
  • anonymous
:)
anonymous
  • anonymous
sure why not?
anonymous
  • anonymous
btw you have my second favorite name on OS
anonymous
  • anonymous
The diagonals of kite KITE intersect at point P. Which statement is true?
sweetburger
  • sweetburger
to find m wouldnt you need to take tan-1(5/12)
sweetburger
  • sweetburger
tan^-1(5/12) sorry typo
anonymous
  • anonymous
Thank you @satellite73 what's your first favorite :)
anonymous
  • anonymous
@sweetburger no
anonymous
  • anonymous
i just said second because i didn't want to totally commit
sweetburger
  • sweetburger
alright
anonymous
  • anonymous
btw i am going to take a stab at this geometry, but no guarantees what are the options for this "which of the following"
anonymous
  • anonymous
A)
anonymous
  • anonymous
going to take a minute to go through all of these
anonymous
  • anonymous
the last one is true for sure
anonymous
  • anonymous
i think that is the only one
anonymous
  • anonymous
i was hoping for more trig
anonymous
  • anonymous
If TUVW is an isosceles trapezoid with TU/ parallel to WV/, name a pair of similar triangles. Explain.
anonymous
  • anonymous
WTV and WUV are similar the diagonals have the same length, TW equals UV and angle W equals angle V
anonymous
  • anonymous
A. triangle UXV= triangle WXT by the SAS similarity theorem. B. triangle TXU= triangle WXV by the SAS similarity theorem. C. triangle WUV= triangle TVW by the AA similarity postulate. D. triangle TXU= triangle VXW by the AA similarity postulate.
anonymous
  • anonymous
ughh... that took a long time.
anonymous
  • anonymous
yeah now let me check
anonymous
  • anonymous
ok first one looks good, but let me keep checking
anonymous
  • anonymous
not B
anonymous
  • anonymous
Ok :)
anonymous
  • anonymous
Verify the identity. cos 4x + cos 2x = 2 - 2 sin2 2x - 2 sin2 x
anonymous
  • anonymous
hold the phone, not done with the previous one (i hate geometry)
anonymous
  • anonymous
same... I hate it too.
anonymous
  • anonymous
cause C looks good too damn lets move on
anonymous
  • anonymous
\[\cos (4x )+ \cos (2x) = 2 - 2 \sin^2( 2x) - 2 \sin^2(x)\] i am a bit confused with the 2's can you post a screen shot or is that it?
anonymous
  • anonymous
hey could we hold off on this problem for a sec, we'll come back to it. Is that fine?
anonymous
  • anonymous
sure
anonymous
  • anonymous
let me guess, more shape...
anonymous
  • anonymous
In the figure,line AB is parallel to line CD. If the area of triangle CED/ is 425, the area of BEA / is 68, and BE = 10, find CE.
1 Attachment
anonymous
  • anonymous
yup lol.
anonymous
  • anonymous
A. 25 B. 36 C. 48 D. 62.5
anonymous
  • anonymous
the big triangle has area 425 and the small one area 68 is that right?
anonymous
  • anonymous
yes
anonymous
  • anonymous
ok we can do this
anonymous
  • anonymous
the ratio of the big area to the small area is \(425:68\) which reduces to \(25:4\) or \(\frac{25}{4}\) the ratio of the sides is therefore the square root of that, namely \( \frac{5}{2}\)
anonymous
  • anonymous
since \(BE=10\) multply it by \(\frac{5}{2}\) and get \(25\)
anonymous
  • anonymous
Yea I did that.
anonymous
  • anonymous
ok good
anonymous
  • anonymous
what do I do next?
anonymous
  • anonymous
have a beer?
anonymous
  • anonymous
pick A we are done, the answer is 25
anonymous
  • anonymous
Find the equation of the circle that has a diameter with endpoints located at (-5,-3) and (-11,-3)
anonymous
  • anonymous
this is much easier
anonymous
  • anonymous
first find the midpoint you got that?
anonymous
  • anonymous
do I have to type in the answer choices...
anonymous
  • anonymous
no we can knock this out in a heartbeat
anonymous
  • anonymous
what is the average of \(-5\) and \(-11\)?
anonymous
  • anonymous
you know what i mean? add them up, divide by 2
anonymous
  • anonymous
lol no
anonymous
  • anonymous
\[-5-11=-16\] \[-16\div 2=-8\]
anonymous
  • anonymous
ok in any case that makes the midpoint \((-8,-3)\) so the equation is \[(x+8)^2+(y+3)^2=r^2\]now we need \(r\)
anonymous
  • anonymous
the distance between \((-8,-3)\) and \((-5,-3)\) is evidently 3 (from -8 to -5 is 3 units) so \(r=3\)
anonymous
  • anonymous
final answer \[(x+8)^2+(y+3)^2=9\]
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
i hate to break it to you but i have no $%#@ing idea
anonymous
  • anonymous
Lol that alright, hold on.
anonymous
  • anonymous
repost i am sure someone knows this and i am sure it is not me
anonymous
  • anonymous
Triangle GHI is similar to triangle JKL. If IH=36 and KP=18, LK=24 then MH=_____. A. 12 B. 20 C. 27 D. 48
1 Attachment
anonymous
  • anonymous
it take goddamn forever just to read it hold on
anonymous
  • anonymous
@satellite73 That's fine for now we'll move on from that problem :) ^
anonymous
  • anonymous
no it is doable give me a sec
anonymous
  • anonymous
Lol alrighty.
anonymous
  • anonymous
\[\frac{18}{24}=\frac{3}{4}\] and so \[\frac{MH}{36}=\frac{3}{4}\] making \[MH=\frac{3\times 36}{4}\]
anonymous
  • anonymous
i hope 27 is a choice
anonymous
  • anonymous
it is ty!
anonymous
  • anonymous
whew did i mention that i hate geometry?
anonymous
  • anonymous
Lol yes you did.
anonymous
  • anonymous
The diagonals of rectangle NOPQ intersect at point R. If OR=3x-4 / and NP=5x+20/, solve for x. A. 2 B. 3 C. 12 D. 28
1 Attachment
anonymous
  • anonymous
\[2\times OR=NP\] pr \[2(3x-4)=5x+20\] solve for \(x\)
anonymous
  • anonymous
*or
anonymous
  • anonymous
6x-8=5x+20 -5x -5x x-8=20 +8 +8 x=28 yay!
anonymous
  • anonymous
yay indeed
anonymous
  • anonymous
Find the volume of a sphere with a diameter 40 cm in length. Approximate pi as 3.14 and round your answer to the nearest tenth. A. 5,026.5 cm^3 B. 33,493.3 cm^3 C. 42,090.0 cm^3 D. 268,082.6 cm^3
anonymous
  • anonymous
google
anonymous
  • anonymous
Lol fine with me.
anonymous
  • anonymous
it comes right up
anonymous
  • anonymous
just plug in the radius, 20
anonymous
  • anonymous
you see it?
anonymous
  • anonymous
Yes!
anonymous
  • anonymous
google give me 33510.32 so i guess it is more exact the using 3.14
anonymous
  • anonymous
Given that WXYZ is a rhombus, find the value of x. A. 15 B. 20 C. 30 D. 45
anonymous
  • anonymous
aaarghhh
anonymous
  • anonymous
oh not arrgghhh
anonymous
  • anonymous
\[4x-10=2x+20\] solve in your head
anonymous
  • anonymous
Lol
anonymous
  • anonymous
got it?
anonymous
  • anonymous
15
anonymous
  • anonymous
bingo
anonymous
  • anonymous
where is all this hell coming from?
anonymous
  • anonymous
If , arC NTM = arc OUM, line SP = line SQ/, S is the center of the circle, and OM = 18, find NT. Round the answer to the hundredths place. A. 11.50 B. 11.92 C. 12.05 D. 12.37
1 Attachment
anonymous
  • anonymous
no clue
anonymous
  • anonymous
Hold on.
anonymous
  • anonymous
Find the value of x. Round the answer to the nearest tenth, if needed. A. 9 B. 18.9 C. 22 D. 32.1
1 Attachment
anonymous
  • anonymous
got logged out
anonymous
  • anonymous
I'll be right back.
anonymous
  • anonymous
this one is ok \[\frac{x}{21}=\frac{49}{x}\] or \[x^2=1029\] making \[x=\sqrt{1029}\]
anonymous
  • anonymous
same I lost connection or something.
anonymous
  • anonymous
site is sometimes bad
anonymous
  • anonymous
Which of the following statements apply to a polygon with eight sides? i. It is a hexagon. ii. It is a heptagon. iii. It is an octagon. iv. It has a total interior angle measure of 1,080º. v. Each interior angle is 135º. A. i, v B. ii, iv C. iii, v D. iii, iv, v
anonymous
  • anonymous
octagon for sure interior angles add to 1080

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