## blackstreet23 one year ago Suppose that the position vector for a particle is given as a function of time by vector r (t) = x(t)i + y(t)j, with x(t) = at + b and y(t) = ct2 + d, where a = 1.30 m/s, b = 1.35 m, c = 0.129 m/s2, and d = 1.14 m. (a) Calculate the average velocity during the time interval from t = 2.05 s to t = 3.95 s.

1. blackstreet23

@freckles @SithsAndGiggles

2. blackstreet23

@Hero

3. blackstreet23

@SolomonZelman

4. IrishBoy123

$$\vec r(t) =< 1.3t + 1.35, \; 0.129t^2 + 1.14>$$ $$\vec r(3.95) - \vec r(2.05) = ???$$ [that is the difference in positions at these two times] $$|\vec r(3.95) - \vec r(2.05)| = ???$$ [that is the actual distance apart at these two times, use Pythagoreas] $$\bar v = \dfrac{|\vec r(3.95) - \vec r(2.05)|}{3.95 - 2.05}$$ [average velocity is distance travelled divided by time]