A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • one year ago

At STP, 0.106 g of a gas sample occupies a volume of 62.2 mL. What is the molar mass of this gas? Keep 3 sig figs for your final answer.

  • This Question is Open
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Is it three sig figs or four?

  2. Photon336
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    Start with the ideal gas equation; we need number of moles n so we solve for n \[pV = nRT \] then our equation becomes this \[\frac{ pV }{ RT } = n \] \[STP = 1 atm, 298K, 25C = Standard temperature and pressure \] plug everything in \[\frac{ pV }{ RT } = n \frac{ 1atm*0.062L }{ (0.08L, atm, mol, * 298) } = 2.54x10^{-3} mol\] we know that 0.00254 moles contains .106 grams but how many grams are in 1 mole. we can do this by setting up a proportion. \[\frac{ mol }{ x,grams } = \frac{ 0.00254,moles }{ 0.106 grams }\] cross multiply \[0.00254 moles, x = 1.06 grams \] 1 mol contains 44.732 grams \[\frac{ 0.106grams }{ 0.00254mol } = 44.732 grams \]

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.