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anonymous
 one year ago
At STP, 0.106 g of a gas sample occupies a volume of 62.2 mL. What is the molar mass of this gas? Keep 3 sig figs for your final answer.
anonymous
 one year ago
At STP, 0.106 g of a gas sample occupies a volume of 62.2 mL. What is the molar mass of this gas? Keep 3 sig figs for your final answer.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is it three sig figs or four?

Photon336
 one year ago
Best ResponseYou've already chosen the best response.3Start with the ideal gas equation; we need number of moles n so we solve for n \[pV = nRT \] then our equation becomes this \[\frac{ pV }{ RT } = n \] \[STP = 1 atm, 298K, 25C = Standard temperature and pressure \] plug everything in \[\frac{ pV }{ RT } = n \frac{ 1atm*0.062L }{ (0.08L, atm, mol, * 298) } = 2.54x10^{3} mol\] we know that 0.00254 moles contains .106 grams but how many grams are in 1 mole. we can do this by setting up a proportion. \[\frac{ mol }{ x,grams } = \frac{ 0.00254,moles }{ 0.106 grams }\] cross multiply \[0.00254 moles, x = 1.06 grams \] 1 mol contains 44.732 grams \[\frac{ 0.106grams }{ 0.00254mol } = 44.732 grams \]
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