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anonymous

  • one year ago

unit step function. #dan815

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  1. anonymous
    • one year ago
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    |dw:1443667583385:dw|

  2. anonymous
    • one year ago
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    just to be clear, we can represent this as X(t)=u(t)+2u(t-1)

  3. dan815
    • one year ago
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    you can rewrite that as a summation of some other step functions

  4. dan815
    • one year ago
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    yes

  5. anonymous
    • one year ago
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    SIK

  6. dan815
    • one year ago
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    uhh lemem see

  7. anonymous
    • one year ago
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    getting the hang of this

  8. anonymous
    • one year ago
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    actual problem is this sox

  9. dan815
    • one year ago
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    |dw:1443667664012:dw|

  10. dan815
    • one year ago
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    yeah what u want to do is actually u(t) + u(t-1)

  11. anonymous
    • one year ago
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    |dw:1443667692857:dw|

  12. anonymous
    • one year ago
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    X(t)=11u(t)+12u(t-1)

  13. dan815
    • one year ago
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    the graph is a bit confusing u want it 10 until 0?

  14. anonymous
    • one year ago
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    10

  15. dan815
    • one year ago
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    what u did will result in 23 at your highest step

  16. anonymous
    • one year ago
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    has constant feed rate of 10m^3/min (theoretically) but at time t=0, a disturbance pushes 1m^3 of water into the tank and an extra 2m^3 of water at t=1min (So an additional 1m^3 of water per min)

  17. dan815
    • one year ago
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    okay lemme get this right though u want 10 before 0?

  18. dan815
    • one year ago
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    u know for laplace transform it cuts off the part before 0

  19. dan815
    • one year ago
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    because if u look at the power series summation n from 0 to inf x^n this only converges when x<1

  20. dan815
    • one year ago
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    |X|<1

  21. anonymous
    • one year ago
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    yea, they draw these graphs just to show use the theoretical flow regime. yes it cuts off at 0 for laplacing, but we have questions that show graphs like these.

  22. anonymous
    • one year ago
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    because another example, where

  23. dan815
    • one year ago
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    okay okay lemme make sure about 1 more thing

  24. dan815
    • one year ago
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    upto where do u want the 10 on the negative side

  25. dan815
    • one year ago
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    forever?

  26. anonymous
    • one year ago
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    |dw:1443668012704:dw|

  27. anonymous
    • one year ago
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    they have function X(t)=90(u(t)-u(t-0.1))

  28. anonymous
    • one year ago
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    so pretty much i just applied it to get X(t)=11u(t)+12u(t-1) but need confirmation

  29. dan815
    • one year ago
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    whats the question again

  30. anonymous
    • one year ago
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    |dw:1443668159355:dw|

  31. dan815
    • one year ago
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    11u(t)+12u(t-1) that wont give u that

  32. anonymous
    • one year ago
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    i just need to find this function as step function

  33. anonymous
    • one year ago
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    so i can solve this silly problem

  34. dan815
    • one year ago
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    lol okay ill show u best way to do this

  35. dan815
    • one year ago
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    just draw some step functions and see how to add them

  36. anonymous
    • one year ago
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    neeeed

  37. anonymous
    • one year ago
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    how about 10(u(t)+2u(t-1))?

  38. anonymous
    • one year ago
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    question is this btw for anyones interest

  39. anonymous
    • one year ago
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  40. anonymous
    • one year ago
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  41. dan815
    • one year ago
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    |dw:1443668206318:dw|

  42. anonymous
    • one year ago
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    10+u(t)+u(t-1)?

  43. dan815
    • one year ago
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    ya that works

  44. anonymous
    • one year ago
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    say we have this drawing again

  45. anonymous
    • one year ago
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    |dw:1443668443342:dw|

  46. dan815
    • one year ago
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    yep

  47. anonymous
    • one year ago
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    they said the step function was x(t)=90(u(t)-u(t-0.1))

  48. dan815
    • one year ago
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    that doesnt work

  49. anonymous
    • one year ago
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    thats the answer....

  50. dan815
    • one year ago
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    they are missing a 10

  51. dan815
    • one year ago
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    plug in a value for t lets say t=2

  52. anonymous
    • one year ago
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  53. anonymous
    • one year ago
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    it legit has it in a book haha , omg I'm confused

  54. dan815
    • one year ago
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    maybe they just dont want to cover the 10, what they have there is

  55. dan815
    • one year ago
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    |dw:1443668705765:dw|

  56. anonymous
    • one year ago
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    perhaps they just shift it down so its just normalises it

  57. anonymous
    • one year ago
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    which really would affect the problem aye

  58. anonymous
    • one year ago
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    wouldn't*

  59. anonymous
    • one year ago
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    |dw:1443668833633:dw|

  60. anonymous
    • one year ago
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    would be X(s)=10u(t)+11u(t-1)

  61. dan815
    • one year ago
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    X(s)=10*U(t)+u(t-1)

  62. anonymous
    • one year ago
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    why isn't it 11u(t-1)? aren't we increasing an addition m^3 after t=1min

  63. anonymous
    • one year ago
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    ohhhhhhh

  64. anonymous
    • one year ago
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    pellet

  65. dan815
    • one year ago
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    lolq

  66. anonymous
    • one year ago
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    yeah cause your steady state value is still at 10

  67. dan815
    • one year ago
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    yes

  68. anonymous
    • one year ago
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    and u just add a step function of magnitude 1 extra YRESSSSDQIDLFYHQBLERBFHIRL

  69. anonymous
    • one year ago
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    DAN u da man

  70. dan815
    • one year ago
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    i beeen telling u this lool

  71. anonymous
    • one year ago
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    shhhhhhhhh

  72. anonymous
    • one year ago
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    hahahahahaa

  73. anonymous
    • one year ago
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    3weeks of lapalce transforms and its a subject inside this course, i rekn I'm doing well to grasp a lot of things haha

  74. anonymous
    • one year ago
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    that just clicked aye

  75. anonymous
    • one year ago
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    nigsss

  76. dan815
    • one year ago
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    lol!

  77. dan815
    • one year ago
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    i think laplace transforms might be a waste of time

  78. dan815
    • one year ago
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    who knows

  79. dan815
    • one year ago
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    its to introduce u to fourier transforms

  80. anonymous
    • one year ago
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    lel, we use lapalce transforms in process control so its easier to solve differential equations (approximate it using linearisation)

  81. dan815
    • one year ago
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    ye but eventually DE become too hard with laplace, so u gotta use fourier transforms for PDES

  82. dan815
    • one year ago
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    i better get back to work T_T

  83. anonymous
    • one year ago
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    yeah tru dat but that was for eng math. i guess we aren't looking at too hard of ODE's but i guess they teach us this smack and we have to learn their way of calculating there questions

  84. anonymous
    • one year ago
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    yea np, peace

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