anonymous
  • anonymous
unit step function. #dan815
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1443667583385:dw|
anonymous
  • anonymous
just to be clear, we can represent this as X(t)=u(t)+2u(t-1)
dan815
  • dan815
you can rewrite that as a summation of some other step functions

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

dan815
  • dan815
yes
anonymous
  • anonymous
SIK
dan815
  • dan815
uhh lemem see
anonymous
  • anonymous
getting the hang of this
anonymous
  • anonymous
actual problem is this sox
dan815
  • dan815
|dw:1443667664012:dw|
dan815
  • dan815
yeah what u want to do is actually u(t) + u(t-1)
anonymous
  • anonymous
|dw:1443667692857:dw|
anonymous
  • anonymous
X(t)=11u(t)+12u(t-1)
dan815
  • dan815
the graph is a bit confusing u want it 10 until 0?
anonymous
  • anonymous
10
dan815
  • dan815
what u did will result in 23 at your highest step
anonymous
  • anonymous
has constant feed rate of 10m^3/min (theoretically) but at time t=0, a disturbance pushes 1m^3 of water into the tank and an extra 2m^3 of water at t=1min (So an additional 1m^3 of water per min)
dan815
  • dan815
okay lemme get this right though u want 10 before 0?
dan815
  • dan815
u know for laplace transform it cuts off the part before 0
dan815
  • dan815
because if u look at the power series summation n from 0 to inf x^n this only converges when x<1
dan815
  • dan815
|X|<1
anonymous
  • anonymous
yea, they draw these graphs just to show use the theoretical flow regime. yes it cuts off at 0 for laplacing, but we have questions that show graphs like these.
anonymous
  • anonymous
because another example, where
dan815
  • dan815
okay okay lemme make sure about 1 more thing
dan815
  • dan815
upto where do u want the 10 on the negative side
dan815
  • dan815
forever?
anonymous
  • anonymous
|dw:1443668012704:dw|
anonymous
  • anonymous
they have function X(t)=90(u(t)-u(t-0.1))
anonymous
  • anonymous
so pretty much i just applied it to get X(t)=11u(t)+12u(t-1) but need confirmation
dan815
  • dan815
whats the question again
anonymous
  • anonymous
|dw:1443668159355:dw|
dan815
  • dan815
11u(t)+12u(t-1) that wont give u that
anonymous
  • anonymous
i just need to find this function as step function
anonymous
  • anonymous
so i can solve this silly problem
dan815
  • dan815
lol okay ill show u best way to do this
dan815
  • dan815
just draw some step functions and see how to add them
anonymous
  • anonymous
neeeed
anonymous
  • anonymous
how about 10(u(t)+2u(t-1))?
anonymous
  • anonymous
question is this btw for anyones interest
anonymous
  • anonymous
anonymous
  • anonymous
dan815
  • dan815
|dw:1443668206318:dw|
anonymous
  • anonymous
10+u(t)+u(t-1)?
dan815
  • dan815
ya that works
anonymous
  • anonymous
say we have this drawing again
anonymous
  • anonymous
|dw:1443668443342:dw|
dan815
  • dan815
yep
anonymous
  • anonymous
they said the step function was x(t)=90(u(t)-u(t-0.1))
dan815
  • dan815
that doesnt work
anonymous
  • anonymous
thats the answer....
dan815
  • dan815
they are missing a 10
dan815
  • dan815
plug in a value for t lets say t=2
anonymous
  • anonymous
anonymous
  • anonymous
it legit has it in a book haha , omg I'm confused
dan815
  • dan815
maybe they just dont want to cover the 10, what they have there is
dan815
  • dan815
|dw:1443668705765:dw|
anonymous
  • anonymous
perhaps they just shift it down so its just normalises it
anonymous
  • anonymous
which really would affect the problem aye
anonymous
  • anonymous
wouldn't*
anonymous
  • anonymous
|dw:1443668833633:dw|
anonymous
  • anonymous
would be X(s)=10u(t)+11u(t-1)
dan815
  • dan815
X(s)=10*U(t)+u(t-1)
anonymous
  • anonymous
why isn't it 11u(t-1)? aren't we increasing an addition m^3 after t=1min
anonymous
  • anonymous
ohhhhhhh
anonymous
  • anonymous
pellet
dan815
  • dan815
lolq
anonymous
  • anonymous
yeah cause your steady state value is still at 10
dan815
  • dan815
yes
anonymous
  • anonymous
and u just add a step function of magnitude 1 extra YRESSSSDQIDLFYHQBLERBFHIRL
anonymous
  • anonymous
DAN u da man
dan815
  • dan815
i beeen telling u this lool
anonymous
  • anonymous
shhhhhhhhh
anonymous
  • anonymous
hahahahahaa
anonymous
  • anonymous
3weeks of lapalce transforms and its a subject inside this course, i rekn I'm doing well to grasp a lot of things haha
anonymous
  • anonymous
that just clicked aye
anonymous
  • anonymous
nigsss
dan815
  • dan815
lol!
dan815
  • dan815
i think laplace transforms might be a waste of time
dan815
  • dan815
who knows
dan815
  • dan815
its to introduce u to fourier transforms
anonymous
  • anonymous
lel, we use lapalce transforms in process control so its easier to solve differential equations (approximate it using linearisation)
dan815
  • dan815
ye but eventually DE become too hard with laplace, so u gotta use fourier transforms for PDES
dan815
  • dan815
i better get back to work T_T
anonymous
  • anonymous
yeah tru dat but that was for eng math. i guess we aren't looking at too hard of ODE's but i guess they teach us this smack and we have to learn their way of calculating there questions
anonymous
  • anonymous
yea np, peace

Looking for something else?

Not the answer you are looking for? Search for more explanations.