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ET365

  • one year ago

So, how do I work the integral(0,6) |3x-6|dx ?

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  1. anonymous
    • one year ago
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    \[\int\limits_{0}^{6}(3x-6)dx\] is this ur integral?

  2. anonymous
    • one year ago
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    if so, you can start integrating. \[\int\limits_{0}^{6}3xdx-\int\limits_{0}^{6}6dx\]

  3. freckles
    • one year ago
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    \[|3x-6|=3x-6 \text{ if } 3x-6 \ge 0 \\ |3x-6|=-(3x-6) \text{ if } 3x-6<0 \\ \text{ solving the inequality part } \\ |3x-6|=3x-6 \text{ if } x \ge 2 \\ |3x-6|=-(3x-6) \text{ if } x<2 \\ \text{ so you have } \int\limits_0^6 |3x-6| dx=\int\limits_0^2 -(3x-6) dx+\int\limits_2^6 (3x-6) dx\]

  4. ET365
    • one year ago
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    Yeah thats it freckles, the integral was the absolute value. Thanks guys!

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