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Anguyennn

  • one year ago

How find find y and x intercepts for the function, x^5+x^2-4X^3-4?

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  1. Anguyennn
    • one year ago
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    \[X ^{5}+X ^{2}-4X ^{3}-4\]

  2. kva1992
    • one year ago
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    if im not mistaken your y int is -4 and for the x intercept id recommend graphing it. you should have 5 x intercepts and the reason your y int is -4 is because you set all the xs to zero

  3. Anguyennn
    • one year ago
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    yes the y intercept is -4

  4. Anguyennn
    • one year ago
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    but how do you get the x intercept algebraically

  5. kva1992
    • one year ago
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    you would have to factor the equation and find all the solutions

  6. Anguyennn
    • one year ago
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    how do you do that? please help!

  7. kva1992
    • one year ago
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    http://www.purplemath.com/modules/solvpoly.htm

  8. kva1992
    • one year ago
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    look at that pretty sure you would have to use synthetic division

  9. Anguyennn
    • one year ago
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    is there another way to do it or no?

  10. kva1992
    • one year ago
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    www.mathportal.org/calculators/solving-equations/polynomial-equation-solver.php?val1=x^5-4x^3plusx^2-4&val2=0&val3=%7Bx%7D^%7B5%7D-4%7Bx%7D^%7B3%7Dplus%7Bx%7D^%7B2%7D-4%3D

  11. Anguyennn
    • one year ago
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    oh alright thank u!!

  12. kva1992
    • one year ago
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    no problem

  13. alekos
    • one year ago
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    one of the x-intercepts is -1 so start of by dividing the polynomial by x+1

  14. triciaal
    • one year ago
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    |dw:1443679224748:dw|

  15. triciaal
    • one year ago
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    x-intercepts (when y = 0 ) -2,2,-1

  16. alekos
    • one year ago
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    nice work!

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