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Pulsified333

  • one year ago

Question involving the selection of two apples from a bag of red and yellow apples without replacement. Assume that the bag has a total of 18 apples: 8 red and 10 yellow. (1) What is the probability that the second apple you pick is red? (2) What is the probability that you pick at least one red apple?

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  1. Pulsified333
    • one year ago
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    @dan815

  2. marco26
    • one year ago
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    Draw a probability tree first.

  3. Pulsified333
    • one year ago
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    |dw:1443696900943:dw|

  4. Pulsified333
    • one year ago
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    I don't know if that is right though

  5. Jadedry
    • one year ago
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    a) The probability that the first apple you pick is red = 8/18 The probability that the second apple you pick is also red = 7/17 Tot Probability= 56/306 --- The probability that the first apple you pick is yellow = 10/18 The probability that the second apple you pick is red = 8/17 Tot Probability = 80/306 --- Added together = 136/306 = 4/9 --- b) calculate the probability that you don't pick any red apples. = 10/18 * 9/17 = 90/306 = 5/17 1- 5/17 =12/17

  6. Pulsified333
    • one year ago
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    oh my why didn't I think about that?

  7. Pulsified333
    • one year ago
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    let me see if that works

  8. Pulsified333
    • one year ago
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    thanks @Jadedry

  9. marco26
    • one year ago
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    Jadedry answers are right. |dw:1443697090611:dw| . Alternatively, you can use probability tree to solve the problem.

  10. Jadedry
    • one year ago
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    @Pulsified333 No problem, happy to help! Remember that if events are dependent on each other, you have to multiply. If they are not, you can add them up.

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