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- Pulsified333

Question involving the selection of two apples from a bag of red and yellow apples without replacement. Assume that the bag has a total of 18 apples: 8 red and 10 yellow.
(1) What is the probability that the second apple you pick is red?
(2) What is the probability that you pick at least one red apple?

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- Pulsified333

- katieb

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- Pulsified333

- marco26

Draw a probability tree first.

- Pulsified333

|dw:1443696900943:dw|

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- Pulsified333

I don't know if that is right though

- Jadedry

a) The probability that the first apple you pick is red = 8/18
The probability that the second apple you pick is also red = 7/17
Tot Probability= 56/306
---
The probability that the first apple you pick is yellow = 10/18
The probability that the second apple you pick is red = 8/17
Tot Probability = 80/306
---
Added together = 136/306 = 4/9
---
b) calculate the probability that you don't pick any red apples.
= 10/18 * 9/17
= 90/306
= 5/17
1- 5/17
=12/17

- Pulsified333

oh my why didn't I think about that?

- Pulsified333

let me see if that works

- Pulsified333

thanks @Jadedry

- marco26

Jadedry answers are right. |dw:1443697090611:dw| . Alternatively, you can use probability tree to solve the problem.

- Jadedry

@Pulsified333
No problem, happy to help!
Remember that if events are dependent on each other, you have to multiply. If they are not, you can add them up.

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