anonymous
  • anonymous
Which of these points lies on a circle centered at A(3, 3) and passing through B(6, 5)? C(1, 6) D(6, 0) E (0, 3) F(3, -1) G(3, 6)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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FireKat97
  • FireKat97
I think the easiest way to approach this, would be firstly to apply the distance formula between A and B (since B lies on the circle and is not the centre, it must lie on the circumference) so by finding this distance, we can determine the radius
FireKat97
  • FireKat97
do you remember the distance formula?
anonymous
  • anonymous
\[2pr ^{2}\]

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FireKat97
  • FireKat97
not quite, thats the circumference formula, we want the distance between two points
FireKat97
  • FireKat97
so the equation you want to use is \[d = \sqrt{(y - y1)^2 + (x - x1)^2}\]
anonymous
  • anonymous
oh yea
FireKat97
  • FireKat97
yup, so apply that and tell me what you get for the distance
anonymous
  • anonymous
3.6
anonymous
  • anonymous
@FireKat97
FireKat97
  • FireKat97
yup, thats correct! but as a general rule, when we get square roots and stuff, you're better off keeping your answer in exact form, so just stick with √13
FireKat97
  • FireKat97
btw do you remember what the general equation of a circle is?
anonymous
  • anonymous
not really
FireKat97
  • FireKat97
okay so the general equation of a circle is- (x - {x coordinate of centre})^2 + (y - {y coordinate of centre})^2 = radius^2
FireKat97
  • FireKat97
and we have been given the centre, and had recently worked out the radius, so try subbing in the info we now have, and show me what you get
anonymous
  • anonymous
2.32?
FireKat97
  • FireKat97
umm, not exactly, so we sub in the stuff we now know to get, (x - 3)^2 + (y - 3)^2 = (√13)^2 so (x - 3)^2 + (y - 3)^2 = 13 do you follow?
anonymous
  • anonymous
yes
FireKat97
  • FireKat97
okay, so now we can try subbing the points given as options into our equation, to see which coordinates satisfy it.
anonymous
  • anonymous
(1,6)
FireKat97
  • FireKat97
Yup! Thats correct!
anonymous
  • anonymous
thankyou!
FireKat97
  • FireKat97
no problem :)

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