An inequality is shown below: -np - 5 ≤ 4(c - 2) Which of the following solves for n? n ≥ - the quantity 4 times c minus 3 all over p n ≥ - the quantity 4 times c minus 13 all over p n ≤ - the quantity 4 times c minus 3 all over p n ≤ - the quantity 4 times c minus 13 all over p

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An inequality is shown below: -np - 5 ≤ 4(c - 2) Which of the following solves for n? n ≥ - the quantity 4 times c minus 3 all over p n ≥ - the quantity 4 times c minus 13 all over p n ≤ - the quantity 4 times c minus 3 all over p n ≤ - the quantity 4 times c minus 13 all over p

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Other answers:

start by distributing 4(c - 2) = ?
4c - 8 ?
good, now we have: -np - 5 ≤ 4c - 8 now add 5 to both sides
okay, the 5 is being added where?
both sides
-np - 5 + 5 ≤ 4c - 8 + 5 keep going
okay so what do I do now?
simplify
-5 + 5 = ?
0 ?
good. -8 + 5 = ?
-3 ?
good, now keep going -np ≤ 4c - 3 now divide both sides by p
okay so it would look like
what?
-np/p = ?
n I mean
-n that gives us -n ≤ (4c - 3)/p now multiply both sides by -1
so multiply the 4c and 3 by -1 ?
no, just put a negative sign in front that gives us -(4c-3)/p
when we multiply or divide by a negative number, the inequality flips, giving us n >= -(4c-3)/p and thats our final answer ~

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