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anonymous

  • one year ago

An inequality is shown below: -np - 5 ≤ 4(c - 2) Which of the following solves for n? n ≥ - the quantity 4 times c minus 3 all over p n ≥ - the quantity 4 times c minus 13 all over p n ≤ - the quantity 4 times c minus 3 all over p n ≤ - the quantity 4 times c minus 13 all over p

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  1. anonymous
    • one year ago
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    |dw:1443722943774:dw|

  2. anonymous
    • one year ago
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    @texaschic101

  3. anonymous
    • one year ago
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    @triciaal

  4. anonymous
    • one year ago
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    @Vocaloid

  5. anonymous
    • one year ago
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    @Michele_Laino

  6. Vocaloid
    • one year ago
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    start by distributing 4(c - 2) = ?

  7. anonymous
    • one year ago
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    4c - 8 ?

  8. Vocaloid
    • one year ago
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    good, now we have: -np - 5 ≤ 4c - 8 now add 5 to both sides

  9. anonymous
    • one year ago
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    okay, the 5 is being added where?

  10. Vocaloid
    • one year ago
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    both sides

  11. Vocaloid
    • one year ago
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    -np - 5 + 5 ≤ 4c - 8 + 5 keep going

  12. anonymous
    • one year ago
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    okay so what do I do now?

  13. Vocaloid
    • one year ago
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    simplify

  14. Vocaloid
    • one year ago
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    -5 + 5 = ?

  15. anonymous
    • one year ago
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    0 ?

  16. Vocaloid
    • one year ago
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    good. -8 + 5 = ?

  17. anonymous
    • one year ago
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    -3 ?

  18. Vocaloid
    • one year ago
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    good, now keep going -np ≤ 4c - 3 now divide both sides by p

  19. anonymous
    • one year ago
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    okay so it would look like

  20. anonymous
    • one year ago
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    what?

  21. Vocaloid
    • one year ago
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    -np/p = ?

  22. anonymous
    • one year ago
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    n I mean

  23. Vocaloid
    • one year ago
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    -n that gives us -n ≤ (4c - 3)/p now multiply both sides by -1

  24. anonymous
    • one year ago
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    so multiply the 4c and 3 by -1 ?

  25. Vocaloid
    • one year ago
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    no, just put a negative sign in front that gives us -(4c-3)/p

  26. Vocaloid
    • one year ago
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    when we multiply or divide by a negative number, the inequality flips, giving us n >= -(4c-3)/p and thats our final answer ~

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