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the vertex lines on the axes of symmetry for a parabola, so first you want to find that and you can do so by using axes of symmetry = -b/2a where y = ax^2 + bx + c
f(x) = 4x2 + 24x + 32 b=24 a=4 -b/2a -24/8
yup thats correct! so now to find the y coordinate that goes with this, we simply sub -24/8 = -3, into the equation, to solve for y
Hmm how did you get the -3 ? Sorry I'm really bad at math !!
Oh thats okay! I just simplified -24/3 because 3 goes into 24, 8 times and we have a minus out the front as well... @ashhhrodriguez
Oh WOW thank you! What exactly do I sub 3 for all the x values ?
I mean -3!
okay so we know that at our axes of symmetry, x = -3, right?
Now we want to sub this back into the equation, to find out what y is equal to as x = -3... agreed?
Ohh so we already have our x value to our vertex -3
yuppp thats what the equation -b/2a gave us
so now we have to find the y value which goes with it
and we can do that by subbing x = -3 back into the original equation
(-3,-4) Thank you so so much !
Yup thats correct! And no problem! :)