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anonymous

  • one year ago

Find the vertex of the graph of the function. f(x) = 4x2 + 24x + 32

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  1. FireKat97
    • one year ago
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    the vertex lines on the axes of symmetry for a parabola, so first you want to find that and you can do so by using axes of symmetry = -b/2a where y = ax^2 + bx + c

  2. FireKat97
    • one year ago
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    lies*

  3. anonymous
    • one year ago
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    f(x) = 4x2 + 24x + 32 b=24 a=4 -b/2a -24/8

  4. FireKat97
    • one year ago
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    yup thats correct! so now to find the y coordinate that goes with this, we simply sub -24/8 = -3, into the equation, to solve for y

  5. anonymous
    • one year ago
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    Hmm how did you get the -3 ? Sorry I'm really bad at math !!

  6. FireKat97
    • one year ago
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    Oh thats okay! I just simplified -24/3 because 3 goes into 24, 8 times and we have a minus out the front as well... @ashhhrodriguez

  7. anonymous
    • one year ago
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    Oh WOW thank you! What exactly do I sub 3 for all the x values ?

  8. anonymous
    • one year ago
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    I mean -3!

  9. FireKat97
    • one year ago
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    okay so we know that at our axes of symmetry, x = -3, right?

  10. FireKat97
    • one year ago
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    Now we want to sub this back into the equation, to find out what y is equal to as x = -3... agreed?

  11. anonymous
    • one year ago
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    Ohh so we already have our x value to our vertex -3

  12. FireKat97
    • one year ago
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    yuppp thats what the equation -b/2a gave us

  13. FireKat97
    • one year ago
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    so now we have to find the y value which goes with it

  14. FireKat97
    • one year ago
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    and we can do that by subbing x = -3 back into the original equation

  15. anonymous
    • one year ago
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    (-3,-4) Thank you so so much !

  16. FireKat97
    • one year ago
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    Yup thats correct! And no problem! :)

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