## ParthKohli one year ago Question for qwerty.

1. anonymous

Maybe I can help??

2. ParthKohli

The center of gravity of a car is at height $$h$$ and the distance between its wheels is $$2a$$. What is the maximum speed with which this car can go around a level curve of radius $$r$$ without overturning?

3. ParthKohli

You've probably done this question before this... the sort of padaaku robot that you are.

4. imqwerty

max speed will be when mv^2/R = normal |dw:1443721650350:dw| nai bhai abhi phy me thoda sa prblm hai but how will we use 2a in this case?

5. ParthKohli

torque :)

6. imqwerty

no idea abt this rn :( we shuld discuss nice phy prblms on sunday :) till then i will complete my back log

7. imqwerty

but how wuld we solve it?

8. ParthKohli

ok, good. here's a rough diagram of the situation.|dw:1443722405447:dw|

9. imqwerty

ok :)

10. ParthKohli

|dw:1443722535476:dw|

11. imqwerty

wait along with mv^2/r will will also add the torque force right

12. imqwerty

but no i donno anythin abt torque rn nd i can't relate the height and use it in the solution

13. ParthKohli

$N_i + N_o = mg\tag{1}$$f = \frac{mv^2}{r}\tag{2}$$N_i (a) + f(h) = N_o (a)\tag{3}$For overturning, the inner wheel loses contact, so $$N_i = 0$$.

14. ParthKohli

The third equation is why torque is so useful.

15. imqwerty

ok :) got it i'll try to finish it up by sunday :) so no os till then :D

16. ParthKohli

No OS till then? OK :( This is related to rotational mechanics

17. imqwerty

yea i've suffered in allen cause of phy nd now its time to finish off the back log :( so no os..till sunday (:

18. ParthKohli

ok, good luck!

19. imqwerty

thanks ^.^

20. anonymous

omg qwertys everywhere >.<