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ParthKohli

  • one year ago

Question for qwerty.

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  1. Defiance
    • one year ago
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    Maybe I can help??

  2. ParthKohli
    • one year ago
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    The center of gravity of a car is at height \(h\) and the distance between its wheels is \(2a\). What is the maximum speed with which this car can go around a level curve of radius \(r\) without overturning?

  3. ParthKohli
    • one year ago
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    You've probably done this question before this... the sort of padaaku robot that you are.

  4. imqwerty
    • one year ago
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    max speed will be when mv^2/R = normal |dw:1443721650350:dw| nai bhai abhi phy me thoda sa prblm hai but how will we use 2a in this case?

  5. ParthKohli
    • one year ago
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    torque :)

  6. imqwerty
    • one year ago
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    no idea abt this rn :( we shuld discuss nice phy prblms on sunday :) till then i will complete my back log

  7. imqwerty
    • one year ago
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    but how wuld we solve it?

  8. ParthKohli
    • one year ago
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    ok, good. here's a rough diagram of the situation.|dw:1443722405447:dw|

  9. imqwerty
    • one year ago
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    ok :)

  10. ParthKohli
    • one year ago
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    |dw:1443722535476:dw|

  11. imqwerty
    • one year ago
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    wait along with mv^2/r will will also add the torque force right

  12. imqwerty
    • one year ago
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    but no i donno anythin abt torque rn nd i can't relate the height and use it in the solution

  13. ParthKohli
    • one year ago
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    \[N_i + N_o = mg\tag{1}\]\[f = \frac{mv^2}{r}\tag{2}\]\[N_i (a) + f(h) = N_o (a)\tag{3}\]For overturning, the inner wheel loses contact, so \(N_i = 0\).

  14. ParthKohli
    • one year ago
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    The third equation is why torque is so useful.

  15. imqwerty
    • one year ago
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    ok :) got it i'll try to finish it up by sunday :) so no os till then :D

  16. ParthKohli
    • one year ago
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    No OS till then? OK :( This is related to rotational mechanics

  17. imqwerty
    • one year ago
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    yea i've suffered in allen cause of phy nd now its time to finish off the back log :( so no os..till sunday (:

  18. ParthKohli
    • one year ago
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    ok, good luck!

  19. imqwerty
    • one year ago
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    thanks ^.^

  20. carlyleukhardt
    • one year ago
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    omg qwertys everywhere >.<

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