anonymous
  • anonymous
Please help. Just need answer. Solve for x. Round to nearest hundredth 5=ln(x+1)
Mathematics
schrodinger
  • schrodinger
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freckles
  • freckles
write in the equivalent exponent form
freckles
  • freckles
\[b=\ln(a) \implies e^{b}=a\]
anonymous
  • anonymous
Would it be 147.41 ??

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freckles
  • freckles
so I guess you wrote in the exponential form... \[e^5=x+1 \\ \text{ last step is \to subtract 1 on both sides } \\ e^5-1=x\] well and then you can approximate the number by rounding to nearest hundredth seems good
anonymous
  • anonymous
So 147.41?
freckles
  • freckles
yes
anonymous
  • anonymous
Yay thank you (:

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