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annmeez

  • one year ago

http://media.edgenuity.com/evresources/2004-06-01-03-00_files/i0390000.jpg Find the surface area of the right square pyramid. Round your answer to the nearest hundredth. A. 117.66 B. 123.21 C. 145.75 D. 182.04

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  1. Vocaloid
    • one year ago
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    start by finding the area of the base

  2. annmeez
    • one year ago
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    i have the area of the rectangular prism

  3. happy_to_help
    • one year ago
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    \[A=a^{2}+2a \sqrt{\frac{ a^{2} }{ 4 }}+h^{2}\] Use this formula A=Base edge H=Height

  4. mathstudent55
    • one year ago
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    The pyramid is a right square pyramid. That means the base is a square. We are shown that all edges of the base measure 5.3 yd. That means you can find the area of the base using the formula for the area of a square. Now you need to find the areas of the 4 triangular sides. All sides are congruent, so you need to find the area of one triangular side, and multiply that area by 4. Each side is a triangle with base 5.3 yd and height 11.1 yd. Use the formula for the area of a triangle with those measures for the base and height, and find the area of one side. Then multiply the area of one side by 4 and add to the area of the square base.

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