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annmeez
 one year ago
http://media.edgenuity.com/evresources/200406010300_files/i0390000.jpg
Find the surface area of the right square pyramid. Round your answer to the nearest hundredth.
A.
117.66
B.
123.21
C.
145.75
D.
182.04
annmeez
 one year ago
http://media.edgenuity.com/evresources/200406010300_files/i0390000.jpg Find the surface area of the right square pyramid. Round your answer to the nearest hundredth. A. 117.66 B. 123.21 C. 145.75 D. 182.04

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Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1start by finding the area of the base

annmeez
 one year ago
Best ResponseYou've already chosen the best response.0i have the area of the rectangular prism

happy_to_help
 one year ago
Best ResponseYou've already chosen the best response.0\[A=a^{2}+2a \sqrt{\frac{ a^{2} }{ 4 }}+h^{2}\] Use this formula A=Base edge H=Height

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1The pyramid is a right square pyramid. That means the base is a square. We are shown that all edges of the base measure 5.3 yd. That means you can find the area of the base using the formula for the area of a square. Now you need to find the areas of the 4 triangular sides. All sides are congruent, so you need to find the area of one triangular side, and multiply that area by 4. Each side is a triangle with base 5.3 yd and height 11.1 yd. Use the formula for the area of a triangle with those measures for the base and height, and find the area of one side. Then multiply the area of one side by 4 and add to the area of the square base.
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