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torii897
 one year ago
please help!!!!!!! I will medal and fan you \
What is the solution to the equation fraction 1 over 6x = 2?
x = fraction 1 over 12 x = fraction 1 over 3 x = 3 x = 12
torii897
 one year ago
please help!!!!!!! I will medal and fan you \ What is the solution to the equation fraction 1 over 6x = 2? x = fraction 1 over 12 x = fraction 1 over 3 x = 3 x = 12

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so, the equation is 1/6x=2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay, the way i do it isnt exactly how the teachers may teach it, but its the way that makes the most sense to me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so, if you want to get 1 than you multiply the 1/6 times 6, so if you multiply that by 2 you get 12, so your answer would be 12

torii897
 one year ago
Best ResponseYou've already chosen the best response.0ah thank you so much can u help with more?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0give me one sec though, this computer is really slow, im just going to switch computers real quick

torii897
 one year ago
Best ResponseYou've already chosen the best response.0The histogram shows the number of prizes won by different numbers of students at a quiz competition. Which of the following statements is correct regarding the number of students and the number of prizes won? A histogram titled Prizes Won is shown. The horizontal axis is labeled Number of Prizes with bins 0 to 5, 6 to 11, 12 to 17, and 18 to 23. The vertical axis labeled Students with values from 0 to 10 at intervals of 1. The first bin goes to 2, the second goes to 7, the third goes to 4, and the last goes to 10. A: A total of 10 students won all the prizes. B :Four students won 12, 13, 14, 15, 16, or 17 prizes. C: A total of 10 prizes were won by all the students. C"Four prizes were won by 12, 13, 14, 15, 16, or 17 students.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would you mind tagging me in this post so it will show up in my notifications?

torii897
 one year ago
Best ResponseYou've already chosen the best response.0did u get the question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but, is the histogram a picture?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it would make it alot easier if you sent the histogram in picture for, drag it to a new tab, then copy th URL and past it in the comments

torii897
 one year ago
Best ResponseYou've already chosen the best response.0http://learn.flvs.net/webdav/assessment_images/educator_mjmath1_v14/mjmath1_exam2_seg2_g13_c2.jpg
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