anonymous
  • anonymous
At noon, the temperature of a container of ether was –109⁰C. At 1 p.m., the temperature of the container of ether was –34⁰C. What was the change in temperature from noon to 1 p.m.? ⁰C
Mathematics
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SOLVED
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chestercat
  • chestercat
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kva1992
  • kva1992
wouldnt you just subtract –109⁰C by –34⁰C?
anonymous
  • anonymous
@alanabrisa
anonymous
  • anonymous
kva1992 is right, you would subtract to get the difference.

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anonymous
  • anonymous
oh, ok
anonymous
  • anonymous
-75? @alanabrisa
anonymous
  • anonymous
Actually hold on a second
anonymous
  • anonymous
Ok so I thinkk, instead of subtracting -109 - (-34), we want to subtract -34 - (-109). Because you want to find the change in temperature from -109 to -34. And since the temperature is rising, it wouldn't make sense for it to be -75. because that means the temperature went down. But if we subtract -34 - (-109) = 75. And it makes more sense if the temperature rose 75 degrees and is now at -34.
anonymous
  • anonymous
Does that kind of make sense or did I ramble too much? lol
kva1992
  • kva1992
err that what i essentially meant lol
kva1992
  • kva1992
essentially you could do it the other way and all you would have to do is multiply a negative to make it positive but you would need to know what you are doing.
anonymous
  • anonymous
ok. so now the answer is -34?
anonymous
  • anonymous
Sorry openstudys giving me a hard time lol So just solve the equation -34 - (-109) = ? Sorry if I confused you
kva1992
  • kva1992
The answer is 75

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