At noon, the temperature of a container of ether was –109⁰C. At 1 p.m., the temperature of the container of ether was –34⁰C. What was the change in temperature from noon to 1 p.m.? ⁰C

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At noon, the temperature of a container of ether was –109⁰C. At 1 p.m., the temperature of the container of ether was –34⁰C. What was the change in temperature from noon to 1 p.m.? ⁰C

Mathematics
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wouldnt you just subtract –109⁰C by –34⁰C?
kva1992 is right, you would subtract to get the difference.

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Other answers:

oh, ok
Actually hold on a second
Ok so I thinkk, instead of subtracting -109 - (-34), we want to subtract -34 - (-109). Because you want to find the change in temperature from -109 to -34. And since the temperature is rising, it wouldn't make sense for it to be -75. because that means the temperature went down. But if we subtract -34 - (-109) = 75. And it makes more sense if the temperature rose 75 degrees and is now at -34.
Does that kind of make sense or did I ramble too much? lol
err that what i essentially meant lol
essentially you could do it the other way and all you would have to do is multiply a negative to make it positive but you would need to know what you are doing.
ok. so now the answer is -34?
Sorry openstudys giving me a hard time lol So just solve the equation -34 - (-109) = ? Sorry if I confused you
The answer is 75

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