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anonymous
 one year ago
At noon, the temperature of a container of ether was –109⁰C. At 1 p.m., the temperature of the container of ether was –34⁰C.
What was the change in temperature from noon to 1 p.m.?
⁰C
anonymous
 one year ago
At noon, the temperature of a container of ether was –109⁰C. At 1 p.m., the temperature of the container of ether was –34⁰C. What was the change in temperature from noon to 1 p.m.? ⁰C

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kva1992
 one year ago
Best ResponseYou've already chosen the best response.0wouldnt you just subtract –109⁰C by –34⁰C?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0kva1992 is right, you would subtract to get the difference.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Actually hold on a second

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok so I thinkk, instead of subtracting 109  (34), we want to subtract 34  (109). Because you want to find the change in temperature from 109 to 34. And since the temperature is rising, it wouldn't make sense for it to be 75. because that means the temperature went down. But if we subtract 34  (109) = 75. And it makes more sense if the temperature rose 75 degrees and is now at 34.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Does that kind of make sense or did I ramble too much? lol

kva1992
 one year ago
Best ResponseYou've already chosen the best response.0err that what i essentially meant lol

kva1992
 one year ago
Best ResponseYou've already chosen the best response.0essentially you could do it the other way and all you would have to do is multiply a negative to make it positive but you would need to know what you are doing.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. so now the answer is 34?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry openstudys giving me a hard time lol So just solve the equation 34  (109) = ? Sorry if I confused you
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