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anonymous

  • one year ago

At noon, the temperature of a container of ether was –109⁰C. At 1 p.m., the temperature of the container of ether was –34⁰C. What was the change in temperature from noon to 1 p.m.? ⁰C

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  1. kva1992
    • one year ago
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    wouldnt you just subtract –109⁰C by –34⁰C?

  2. anonymous
    • one year ago
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    @alanabrisa

  3. anonymous
    • one year ago
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    kva1992 is right, you would subtract to get the difference.

  4. anonymous
    • one year ago
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    oh, ok

  5. anonymous
    • one year ago
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    -75? @alanabrisa

  6. anonymous
    • one year ago
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    Actually hold on a second

  7. anonymous
    • one year ago
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    Ok so I thinkk, instead of subtracting -109 - (-34), we want to subtract -34 - (-109). Because you want to find the change in temperature from -109 to -34. And since the temperature is rising, it wouldn't make sense for it to be -75. because that means the temperature went down. But if we subtract -34 - (-109) = 75. And it makes more sense if the temperature rose 75 degrees and is now at -34.

  8. anonymous
    • one year ago
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    Does that kind of make sense or did I ramble too much? lol

  9. kva1992
    • one year ago
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    err that what i essentially meant lol

  10. kva1992
    • one year ago
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    essentially you could do it the other way and all you would have to do is multiply a negative to make it positive but you would need to know what you are doing.

  11. anonymous
    • one year ago
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    ok. so now the answer is -34?

  12. anonymous
    • one year ago
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    Sorry openstudys giving me a hard time lol So just solve the equation -34 - (-109) = ? Sorry if I confused you

  13. kva1992
    • one year ago
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    The answer is 75

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