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anonymous

  • one year ago

HELP MEDAL GIVEN !!!!!!!

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  1. anonymous
    • one year ago
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    what mass of sulphur has the same number of atoms as 6g of magnesium ?

  2. anonymous
    • one year ago
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    @ParthKohli @pooja195 @Photon336

  3. Photon336
    • one year ago
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    For any element one mole will have \[\frac{ 1,mol }{ 6.02x10^{23} atoms}\] \[\frac{ 1, mol, sulphur }{ 32grams } = (6.02x10^{23} atoms, of, sulphur )\] Let's do the same thing for magnesium. \[\frac{ 1,mol,magnesium }{ 24.0 grams, magnesium } = 6.02x10^{23} atoms of magnesium \] I think you would do it like this in a ratio: \[\frac{ 6.02x10^{23} atoms, mg}{ 24.0 g,mg } = \frac{ x,atoms }{ 6.0g. mg }\] 6.0g Mg*6.02x10^23 atoms = 24.0g Mg * (x)

  4. Photon336
    • one year ago
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    \[\frac{ 6 }{ 24 } = \frac{ 1 }{ 4 }*(6.02x10^{23})atoms = 1.505x10^{23} atoms of mg\]

  5. Photon336
    • one year ago
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    I think we would set up another proportion. we need to figure out what mass of sulphur is equivalent to the number of atoms. \[\frac{ 32grams }{ 6.02x10^{23} sulphur } = \frac{ x,grams }{ 1.505x10^{23} atoms }\]

  6. Photon336
    • one year ago
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    \[\frac{ 4.816x10^{24} }{ 6.02x10^{23} } = 8.0, grams, of, sulphur \]

  7. Photon336
    • one year ago
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    @ryanvarghese12790

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