Pulsified333
  • Pulsified333
Assume that you have 5 red balls and 4 blue balls from which randomly to select two without replacement. (1) What is the probability that exactly one red ball is chosen? (2) What is the probability that the second ball is blue given that at least one of the balls is blue?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
there are a couple ways to do this perhaps the most intuitive way is to calculate the probability that the first ball is red and the second is not then the probability that the first is not red, and the second is do you know how to do that?
Pulsified333
  • Pulsified333
i just got the first part but the second part I'm not sure how to do
anonymous
  • anonymous
guess we need some notation

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anonymous
  • anonymous
actually a diagram would be bets lets see if i can draw one
Pulsified333
  • Pulsified333
ok
anonymous
  • anonymous
actually no, lets just do it easy you have already computed the probability that exactly one ball is blue right?
anonymous
  • anonymous
what did you get, and how did you do it?
Pulsified333
  • Pulsified333
I got 5/9
anonymous
  • anonymous
the probability that both balls are blue is \[\frac{4}{9}\times \frac{3}{8}=\frac{1}{6}\]
anonymous
  • anonymous
the probability that the first is blue and the second is red is \[\frac{4}{9}\times \frac{5}{8}=\frac{5}{18}\]
anonymous
  • anonymous
and the probability that the first is red and the second is blue is the same \[\frac{5}{18}\] add these up to get the probability that at least one is blue
anonymous
  • anonymous
you need that for your denominator
Pulsified333
  • Pulsified333
so 1/6+5/18
anonymous
  • anonymous
no it is \[\frac{1}{6}+\frac{5}{18}+\frac{5}{18}\]
Pulsified333
  • Pulsified333
oh
Pulsified333
  • Pulsified333
the answer would be 13/18
anonymous
  • anonymous
ok good so that is your denominator
anonymous
  • anonymous
your numerator is the probability that the second ball is blue
Pulsified333
  • Pulsified333
so 4/9
anonymous
  • anonymous
yes
Pulsified333
  • Pulsified333
8/13?
anonymous
  • anonymous
that is what i get, yes
Pulsified333
  • Pulsified333
:D it was right thanks man.
anonymous
  • anonymous
yw nothing like instant gratification !
Pulsified333
  • Pulsified333
btw if i want to send you a message how do i do that?
anonymous
  • anonymous
you cannot
Pulsified333
  • Pulsified333
;(
anonymous
  • anonymous
you can tag me in a question if you like @satellite73
Pulsified333
  • Pulsified333
okay I'm going to be posting a lot of problems tonight because I have a midterm tomorrow that I have not even studied for yet and I pulled an all nighter last night to work on a presentation that I had to present today and study for a test that i took today.
anonymous
  • anonymous
yikes
Pulsified333
  • Pulsified333
@satellite73 I know. Right now I'm scared that I am going to have to stop doing my math hw and study for the test and take the fail on the hw

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