anonymous
  • anonymous
Suppose the integral from 2 to 8 of g of x, dx equals 13, and the integral from 6 to 8 of g of x, dx equals negative 3, find the value of 2 plus the integral from 2 to 6 of g of x, dx.
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
https://gyazo.com/41bc06711b55841c5edc26d60f3d956a
freckles
  • freckles
\[\int\limits_2^6g(x) dx=\int\limits_2^8 g(x) dx- \int\limits_6^8 g(x)dx\]
freckles
  • freckles
we have from 2 to 8 given but we wanted 2 to 6 so we have to subtract the part out that is from 6 to 8

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freckles
  • freckles
which is given also
freckles
  • freckles
don't forget to add the 2 in
anonymous
  • anonymous
So how would go about to solve? Solve each integral then subtract?
anonymous
  • anonymous
no just subtract
anonymous
  • anonymous
Oooooooooohhhhhhh I'm an idiot, read the question so wrong. 16+2=18 Final answer 18 right?
freckles
  • freckles
right you have 2+13-(-3) which is 15+3 which is 18

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