chris215
  • chris215
To three decimal places, find the value of the first positive x-intercept for the function f(x) = 2cos(x + 3).
Mathematics
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SOLVED
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chestercat
  • chestercat
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chris215
  • chris215
I got -1.429 but i think that's wrong
anonymous
  • anonymous
it has to be wrong, since it is not positive
anonymous
  • anonymous
\[2\cos(x+2)=0\\ \cos(x+2)=0\\ x+2=\frac{\pi}{2}\] i guess that gives you the negative answer right?

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anonymous
  • anonymous
try \[x+2=\frac{5\pi}{2}\]

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