## chris215 one year ago To three decimal places, find the value of the first positive x-intercept for the function f(x) = 2cos(x + 3).

1. chris215

I got -1.429 but i think that's wrong

2. anonymous

it has to be wrong, since it is not positive

3. anonymous

$2\cos(x+2)=0\\ \cos(x+2)=0\\ x+2=\frac{\pi}{2}$ i guess that gives you the negative answer right?

4. anonymous

try $x+2=\frac{5\pi}{2}$