## owlet one year ago Am I right? check below:

1. owlet

2. owlet

@freckles @Jhannybean I just wanted to know if my domain for the inverse is right or not...

3. carlyleukhardt

Its kind of messy XD

4. anonymous

5. anonymous

both parts

6. owlet

okay thank you. I learned something from you yesterday :)

7. Jhannybean

Instead of writing it as $$y=\dfrac{\ln\left(\dfrac{x+1}{3}\right)-1}{2}$$, I would write $$y= \dfrac{\ln(x+1)-\ln(3)-1}{2}$$

8. Jhannybean

Otherwise it looks great!

9. owlet

thank you so much for all your help :)