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owlet
 one year ago
Am I right? check below:
owlet
 one year ago
Am I right? check below:

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owlet
 one year ago
Best ResponseYou've already chosen the best response.0@freckles @Jhannybean I just wanted to know if my domain for the inverse is right or not...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Its kind of messy XD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0your answer is correct

owlet
 one year ago
Best ResponseYou've already chosen the best response.0okay thank you. I learned something from you yesterday :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Instead of writing it as \(y=\dfrac{\ln\left(\dfrac{x+1}{3}\right)1}{2}\), I would write \(y= \dfrac{\ln(x+1)\ln(3)1}{2}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Otherwise it looks great!

owlet
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much for all your help :)
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