owlet
  • owlet
Am I right? check below:
Mathematics
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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owlet
  • owlet
Am I right? check below:
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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owlet
  • owlet
1 Attachment
owlet
  • owlet
@freckles @Jhannybean I just wanted to know if my domain for the inverse is right or not...
carlyleukhardt
  • carlyleukhardt
Its kind of messy XD

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anonymous
  • anonymous
your answer is correct
anonymous
  • anonymous
both parts
owlet
  • owlet
okay thank you. I learned something from you yesterday :)
Jhannybean
  • Jhannybean
Instead of writing it as \(y=\dfrac{\ln\left(\dfrac{x+1}{3}\right)-1}{2}\), I would write \(y= \dfrac{\ln(x+1)-\ln(3)-1}{2}\)
Jhannybean
  • Jhannybean
Otherwise it looks great!
owlet
  • owlet
thank you so much for all your help :)

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