Pulsified333
  • Pulsified333
Assume that each bag contains 5 balls. Bag a contains 1 red and 4 white, while bag b contains 1 red, 2 white, and 2 blue. You randomly select one ball from bag a, note the color, and place the ball in bag b. You then select a ball from bag b at random and make note of its color. (1) What is the probability that both balls are red? (2) What is the probability that both balls are red given that the first ball you drew was red?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
you got a lot of work to do
anonymous
  • anonymous
oh nvm the first one is not that hard at all
anonymous
  • anonymous
what is the probably the first ball is red?

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anonymous
  • anonymous
Chance of getting a red ball from bag A --> 3/5 Place red ball into bag B --> Bag B now has 6 balls, 2 of which are red. Chance of getting a red ball from bag B --> 2/6 = 1/3 Chance of both events being true --> (3/5) * (1/3) = 1/5 I'm not sure if that's right.
Pulsified333
  • Pulsified333
yeah I know. As you might expect my brain isn't functioning at its best right now but I am trying
anonymous
  • anonymous
@SataniCross idea is right, you number is wrong
anonymous
  • anonymous
that's what i thought
anonymous
  • anonymous
only the first number you put \(\frac{3}{5}\) but it should be \(\frac{1}{5}\)
anonymous
  • anonymous
you got this? or you want to walk through it?
Pulsified333
  • Pulsified333
would 1 be 1/15?
anonymous
  • anonymous
\[\frac{1}{5}\times \frac{2}{6}\] yeah you are n right
Pulsified333
  • Pulsified333
then for 2, Would it be (1/15)/(1/5)?
anonymous
  • anonymous
yes
Pulsified333
  • Pulsified333
:D thanks
anonymous
  • anonymous
yw you did all the work
Pulsified333
  • Pulsified333
yeah but you helped with explaining the technique on the previous problem :D

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