## Pulsified333 one year ago Assume that each bag contains 5 balls. Bag a contains 1 red and 4 white, while bag b contains 1 red, 2 white, and 2 blue. You randomly select one ball from bag a, note the color, and place the ball in bag b. You then select a ball from bag b at random and make note of its color. (1) What is the probability that both balls are red? (2) What is the probability that both balls are red given that the first ball you drew was red?

1. anonymous

you got a lot of work to do

2. anonymous

oh nvm the first one is not that hard at all

3. anonymous

what is the probably the first ball is red?

4. anonymous

Chance of getting a red ball from bag A --> 3/5 Place red ball into bag B --> Bag B now has 6 balls, 2 of which are red. Chance of getting a red ball from bag B --> 2/6 = 1/3 Chance of both events being true --> (3/5) * (1/3) = 1/5 I'm not sure if that's right.

5. Pulsified333

yeah I know. As you might expect my brain isn't functioning at its best right now but I am trying

6. anonymous

@SataniCross idea is right, you number is wrong

7. anonymous

that's what i thought

8. anonymous

only the first number you put $$\frac{3}{5}$$ but it should be $$\frac{1}{5}$$

9. anonymous

you got this? or you want to walk through it?

10. Pulsified333

would 1 be 1/15?

11. anonymous

$\frac{1}{5}\times \frac{2}{6}$ yeah you are n right

12. Pulsified333

then for 2, Would it be (1/15)/(1/5)?

13. anonymous

yes

14. Pulsified333

:D thanks

15. anonymous

yw you did all the work

16. Pulsified333

yeah but you helped with explaining the technique on the previous problem :D