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Pulsified333
 one year ago
Assume that each bag contains 5 balls. Bag a contains 1 red and 4 white, while bag b contains 1 red, 2 white, and 2 blue. You randomly select one ball from bag a, note the color, and place the ball in bag b. You then select a ball from bag b at random and make note of its color.
(1) What is the probability that both balls are red?
(2) What is the probability that both balls are red given that the first ball you drew was red?
Pulsified333
 one year ago
Assume that each bag contains 5 balls. Bag a contains 1 red and 4 white, while bag b contains 1 red, 2 white, and 2 blue. You randomly select one ball from bag a, note the color, and place the ball in bag b. You then select a ball from bag b at random and make note of its color. (1) What is the probability that both balls are red? (2) What is the probability that both balls are red given that the first ball you drew was red?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you got a lot of work to do

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh nvm the first one is not that hard at all

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what is the probably the first ball is red?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Chance of getting a red ball from bag A > 3/5 Place red ball into bag B > Bag B now has 6 balls, 2 of which are red. Chance of getting a red ball from bag B > 2/6 = 1/3 Chance of both events being true > (3/5) * (1/3) = 1/5 I'm not sure if that's right.

Pulsified333
 one year ago
Best ResponseYou've already chosen the best response.0yeah I know. As you might expect my brain isn't functioning at its best right now but I am trying

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@SataniCross idea is right, you number is wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's what i thought

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0only the first number you put \(\frac{3}{5}\) but it should be \(\frac{1}{5}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you got this? or you want to walk through it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{1}{5}\times \frac{2}{6}\] yeah you are n right

Pulsified333
 one year ago
Best ResponseYou've already chosen the best response.0then for 2, Would it be (1/15)/(1/5)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yw you did all the work

Pulsified333
 one year ago
Best ResponseYou've already chosen the best response.0yeah but you helped with explaining the technique on the previous problem :D
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