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Pulsified333

  • one year ago

Assume that each bag contains 5 balls. Bag a contains 1 red and 4 white, while bag b contains 1 red, 2 white, and 2 blue. You randomly select one ball from bag a, note the color, and place the ball in bag b. You then select a ball from bag b at random and make note of its color. (1) What is the probability that both balls are red? (2) What is the probability that both balls are red given that the first ball you drew was red?

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  1. anonymous
    • one year ago
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    you got a lot of work to do

  2. anonymous
    • one year ago
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    oh nvm the first one is not that hard at all

  3. anonymous
    • one year ago
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    what is the probably the first ball is red?

  4. anonymous
    • one year ago
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    Chance of getting a red ball from bag A --> 3/5 Place red ball into bag B --> Bag B now has 6 balls, 2 of which are red. Chance of getting a red ball from bag B --> 2/6 = 1/3 Chance of both events being true --> (3/5) * (1/3) = 1/5 I'm not sure if that's right.

  5. Pulsified333
    • one year ago
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    yeah I know. As you might expect my brain isn't functioning at its best right now but I am trying

  6. anonymous
    • one year ago
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    @SataniCross idea is right, you number is wrong

  7. anonymous
    • one year ago
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    that's what i thought

  8. anonymous
    • one year ago
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    only the first number you put \(\frac{3}{5}\) but it should be \(\frac{1}{5}\)

  9. anonymous
    • one year ago
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    you got this? or you want to walk through it?

  10. Pulsified333
    • one year ago
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    would 1 be 1/15?

  11. anonymous
    • one year ago
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    \[\frac{1}{5}\times \frac{2}{6}\] yeah you are n right

  12. Pulsified333
    • one year ago
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    then for 2, Would it be (1/15)/(1/5)?

  13. anonymous
    • one year ago
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    yes

  14. Pulsified333
    • one year ago
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    :D thanks

  15. anonymous
    • one year ago
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    yw you did all the work

  16. Pulsified333
    • one year ago
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    yeah but you helped with explaining the technique on the previous problem :D

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