anonymous
  • anonymous
Find the x-intercepts (if any) for the graph of the quadratic function. 6x2 + 12x + 5 = 0 Give your answers in exact form. Show your work.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@Hero @dan815
anonymous
  • anonymous
@Jhannybean @satellite73 @Loser66 @freckles @EclipsedStar @King.Void. @sleepyjess can someone help me please?
sleepyjess
  • sleepyjess
Do you have an idea on how to start?

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More answers

anonymous
  • anonymous
no not at all
sleepyjess
  • sleepyjess
Do you know what the quadratic formula is?
anonymous
  • anonymous
what you mean?
sleepyjess
  • sleepyjess
\(x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\)
sleepyjess
  • sleepyjess
That is the quadratic formula
sleepyjess
  • sleepyjess
It may look intimidating, but it's not too bad once you know how to work it :)
anonymous
  • anonymous
Okay how do I work it lol..
sleepyjess
  • sleepyjess
A quadratic equation is ALWAYS "Ax^2 + Bx + C = y" To use the quadratic formula, you will want to substitute 0 for y, which has already been done. Can you figure out what A, B, and C are in the quadratic equation you have?
anonymous
  • anonymous
A= 6x^2 B= 12x C= 5
sleepyjess
  • sleepyjess
Close, but we just want 6, 12 and 5
anonymous
  • anonymous
Ohh lol
sleepyjess
  • sleepyjess
So now we just substitute in 6 for a, 12 for b, and 5 for c then work out the equation
anonymous
  • anonymous
I got down to \[x= \frac{ -12\pm \sqrt{24} }{ 12 }\] now what do I do?
anonymous
  • anonymous
@sleepyjess
carolinar7
  • carolinar7
Now simplify what you have there
anonymous
  • anonymous
How?
carolinar7
  • carolinar7
\[x=\frac{ -12-+4\sqrt{6} }{ 12 }\]
carolinar7
  • carolinar7
Can you simplify any further?
anonymous
  • anonymous
Why 4 sqrt7 instead of sqrt24=4.89....?
anonymous
  • anonymous
I meant sqrt6 sorry
carolinar7
  • carolinar7
Sorry let me correct myself it is 2sqrt6
carolinar7
  • carolinar7
Is this Alg. 1
anonymous
  • anonymous
How!? And no its pre-calculus
carolinar7
  • carolinar7
what grade ar you in
anonymous
  • anonymous
@sleepyjess please help me, I don't understand!!
carolinar7
  • carolinar7
me too im in pre-calc in 9th grade
sleepyjess
  • sleepyjess
oh goodness, I forgot about the square root simplifying >_<
anonymous
  • anonymous
How do I do that?
sleepyjess
  • sleepyjess
@carolinar7 simplified it for you
carolinar7
  • carolinar7
what do you mean you simplified it for me
sleepyjess
  • sleepyjess
you simplified the square root already
anonymous
  • anonymous
2 sqrt6?
carolinar7
  • carolinar7
It is not completely simplified though, you can simplify further too
carolinar7
  • carolinar7
\[x=\frac{ -6+-\sqrt{6} }{ 6 }\]
anonymous
  • anonymous
so where do I go from \[x= \frac{ -12 \pm 2\sqrt{6} }{ 12 }\]
anonymous
  • anonymous
Ohhh how did you get that?
carolinar7
  • carolinar7
You simplify it and divide by 2 because that is what they share in common
anonymous
  • anonymous
Ohhh okay soo now I do -6/6?
carolinar7
  • carolinar7
|dw:1443753373282:dw|
carolinar7
  • carolinar7
no you cant simplify any further
anonymous
  • anonymous
so thats the exact form?
carolinar7
  • carolinar7
Wait let me do it on a paper
carolinar7
  • carolinar7
Yes that is the most you can simplify it
anonymous
  • anonymous
Okay thank you!
carolinar7
  • carolinar7
yup

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