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anonymous

  • one year ago

Find the x-intercepts (if any) for the graph of the quadratic function. 6x2 + 12x + 5 = 0 Give your answers in exact form. Show your work.

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  1. anonymous
    • one year ago
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    @Hero @dan815

  2. anonymous
    • one year ago
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    @Jhannybean @satellite73 @Loser66 @freckles @EclipsedStar @King.Void. @sleepyjess can someone help me please?

  3. sleepyjess
    • one year ago
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    Do you have an idea on how to start?

  4. anonymous
    • one year ago
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    no not at all

  5. sleepyjess
    • one year ago
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    Do you know what the quadratic formula is?

  6. anonymous
    • one year ago
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    what you mean?

  7. sleepyjess
    • one year ago
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    \(x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\)

  8. sleepyjess
    • one year ago
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    That is the quadratic formula

  9. sleepyjess
    • one year ago
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    It may look intimidating, but it's not too bad once you know how to work it :)

  10. anonymous
    • one year ago
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    Okay how do I work it lol..

  11. sleepyjess
    • one year ago
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    A quadratic equation is ALWAYS "Ax^2 + Bx + C = y" To use the quadratic formula, you will want to substitute 0 for y, which has already been done. Can you figure out what A, B, and C are in the quadratic equation you have?

  12. anonymous
    • one year ago
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    A= 6x^2 B= 12x C= 5

  13. sleepyjess
    • one year ago
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    Close, but we just want 6, 12 and 5

  14. anonymous
    • one year ago
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    Ohh lol

  15. sleepyjess
    • one year ago
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    So now we just substitute in 6 for a, 12 for b, and 5 for c then work out the equation

  16. anonymous
    • one year ago
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    I got down to \[x= \frac{ -12\pm \sqrt{24} }{ 12 }\] now what do I do?

  17. anonymous
    • one year ago
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    @sleepyjess

  18. carolinar7
    • one year ago
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    Now simplify what you have there

  19. anonymous
    • one year ago
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    How?

  20. carolinar7
    • one year ago
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    \[x=\frac{ -12-+4\sqrt{6} }{ 12 }\]

  21. carolinar7
    • one year ago
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    Can you simplify any further?

  22. anonymous
    • one year ago
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    Why 4 sqrt7 instead of sqrt24=4.89....?

  23. anonymous
    • one year ago
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    I meant sqrt6 sorry

  24. carolinar7
    • one year ago
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    Sorry let me correct myself it is 2sqrt6

  25. carolinar7
    • one year ago
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    Is this Alg. 1

  26. anonymous
    • one year ago
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    How!? And no its pre-calculus

  27. carolinar7
    • one year ago
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    what grade ar you in

  28. anonymous
    • one year ago
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    @sleepyjess please help me, I don't understand!!

  29. carolinar7
    • one year ago
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    me too im in pre-calc in 9th grade

  30. sleepyjess
    • one year ago
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    oh goodness, I forgot about the square root simplifying >_<

  31. anonymous
    • one year ago
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    How do I do that?

  32. sleepyjess
    • one year ago
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    @carolinar7 simplified it for you

  33. carolinar7
    • one year ago
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    what do you mean you simplified it for me

  34. sleepyjess
    • one year ago
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    you simplified the square root already

  35. anonymous
    • one year ago
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    2 sqrt6?

  36. carolinar7
    • one year ago
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    It is not completely simplified though, you can simplify further too

  37. carolinar7
    • one year ago
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    \[x=\frac{ -6+-\sqrt{6} }{ 6 }\]

  38. anonymous
    • one year ago
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    so where do I go from \[x= \frac{ -12 \pm 2\sqrt{6} }{ 12 }\]

  39. anonymous
    • one year ago
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    Ohhh how did you get that?

  40. carolinar7
    • one year ago
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    You simplify it and divide by 2 because that is what they share in common

  41. anonymous
    • one year ago
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    Ohhh okay soo now I do -6/6?

  42. carolinar7
    • one year ago
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    |dw:1443753373282:dw|

  43. carolinar7
    • one year ago
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    no you cant simplify any further

  44. anonymous
    • one year ago
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    so thats the exact form?

  45. carolinar7
    • one year ago
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    Wait let me do it on a paper

  46. carolinar7
    • one year ago
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    Yes that is the most you can simplify it

  47. anonymous
    • one year ago
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    Okay thank you!

  48. carolinar7
    • one year ago
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    yup

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