anonymous
  • anonymous
Events E and F in a sample space S. Assume that Pr[E]=17/30, Pr[F|E]=12/17, and Pr[E′∩F′]=1/5. (1) Pr[F]= (2) Pr[E∩F]=
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
#2 is 102/255
sleepyjess
  • sleepyjess
Welcome to OpenStudy! I'm not sure on this, but maybe @freckles or @hero can help :)
freckles
  • freckles
what!?! what is PR mean? Please don't say probability.

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anonymous
  • anonymous
question makes no sense to me, a probability is never larger than 1
anonymous
  • anonymous
sorry i fixed it @satellite73
anonymous
  • anonymous
that's better
anonymous
  • anonymous
\[P(F|E)=\frac{P(F\cap E)}{P(E)}\]
anonymous
  • anonymous
you can use that to find \[P(F\cap E)\]
anonymous
  • anonymous
i already found F∩E which is 102/255
anonymous
  • anonymous
oh no !
anonymous
  • anonymous
\[P(F\cap E)=\frac{17}{30}\times \frac{12}{17}=\frac{12}{30}=\frac{2}{5}\]
Pulsified333
  • Pulsified333
@satellite73 isn't P(F∩E) = Pr(F|E) * Pr(E)?

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