calculusxy
  • calculusxy
Exponents question (will be attached below) MEDAL will be award
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
calculusxy
  • calculusxy
\[\frac{ y^{-1} \times -x^4y^3 }{ (x^0y^3)^3 }\]
calculusxy
  • calculusxy
@satellite73
calculusxy
  • calculusxy
@Hero @AbdullahM

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

calculusxy
  • calculusxy
the answer key says that the answer is \[-\frac{ x^4 }{ y^7 }\] but i get the same answer but positive
Hero
  • Hero
-x^4 is negative so the final result will be negative.
calculusxy
  • calculusxy
but doesn't the eve n number exponent turn the negative base into a positive?
calculusxy
  • calculusxy
@Hero
Hero
  • Hero
The negative In front of \(-x^4\) is not in front of an exponent -x^4 Is different from \(x^{-4}\)
calculusxy
  • calculusxy
so if it was in front of the exponent then it would have become \[\frac{ 1 }{ x^4 }\]?
chrisplusian
  • chrisplusian
If it was attached to the exponent then yes
chrisplusian
  • chrisplusian
So to summarize \[(-x)^{2}\neq-x^2\] and \[x^{-2}=\frac{ 1 }{ x^2 }\]
chrisplusian
  • chrisplusian
When dealing with negative NUMBERS and positive exponents the rule is this: The exponent only attaches to the NUMBER or the parentheses. It does not attach to the sign. If you want the sign to be included in the operation with the exponent then you must have the sign in the parentheses.... Like this...
chrisplusian
  • chrisplusian
\[-x^2=-(x)(x)=-x^2\]
chrisplusian
  • chrisplusian
\[(-x)^2=(-x)(-x)=x^2\]
chrisplusian
  • chrisplusian
\[-(x)^2=-(x)(x)=-x^2\]
chrisplusian
  • chrisplusian
So the exponent makes the thing it is attached to repeatedly multiply the number of times the exponent says. It will only attach to a number, or set pf parentheses. If it attaches to the number only repeatedly multiply the number and not the sign. If the exponent is attached to the parentheses then repeatedly multiply whatever is in the parentheses. Hope that helps
AbdullahM
  • AbdullahM
@calculusxy did you understand this question? :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.