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Destinyyyy

  • one year ago

In 2000, 51% of the residents in a large city regularly used newspapers for getting news and this has decrease at an average rate of approximately 1.6% per year since then. Find a linear function in slope- inter form that models this description. The function should model the percentage of residents, P(x), who regularly used the newspaper outlet x years after 2000.

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  1. Destinyyyy
    • one year ago
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    Need a refresher.. Don't really remember how to solve this one.

  2. Destinyyyy
    • one year ago
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    @freckles

  3. Destinyyyy
    • one year ago
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    @Nnesha

  4. freckles
    • one year ago
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    So at t=0 we have the year 2000 and we are given at t=0 the percentage was 51% or .51 we are also given the percentage decreases per year by 1.6% aka 0.016 So at t=1 aka year 2001 what would be the new percentage?

  5. Destinyyyy
    • one year ago
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    Not a clue.

  6. freckles
    • one year ago
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    well it is the very next year and we are given the percentage decreases by 0.016 per year

  7. freckles
    • one year ago
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    so since at t=0 we had y=.51 then at t=1 we have y=.51-0.016 since this is the very next year the next year after that t=2 we would have y=.51-2(0.016)

  8. Destinyyyy
    • one year ago
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    I thought for this problem I have to do the f(x1)- f(x2) thing

  9. freckles
    • one year ago
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    for this problem they are asking you to find the line that represents the information the line being of the form y=mx+b where m is the rate aka slope and b is the y-intercept

  10. freckles
    • one year ago
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    you are actually given the rate which is -0.016

  11. freckles
    • one year ago
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    y=-0.016x+b you just need to find b now

  12. Destinyyyy
    • one year ago
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    Um okay? Then I have absolutely no clue how to solve this. I have no examples. And this is the unit review.

  13. freckles
    • one year ago
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    well did you understand at t=0 we have .51?

  14. Destinyyyy
    • one year ago
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    No because I don't get what "t" stands for..

  15. freckles
    • one year ago
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    t is the time

  16. freckles
    • one year ago
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    in years

  17. freckles
    • one year ago
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    after 2000

  18. Destinyyyy
    • one year ago
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    Oh..

  19. freckles
    • one year ago
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    and since I'm looking at the year 2000 and the question says find an equation for t years after 2000 then then year 2000 is actually when time=0

  20. freckles
    • one year ago
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    or I used t for time variable so t=0

  21. Destinyyyy
    • one year ago
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    Okay

  22. freckles
    • one year ago
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    (0,.51) is the first point on the graph (1,.51-.016) is the next point on the graph because we are given the rate of decrease is .016 do you understand this part? In year 2001, the very next year after 2000 we will have a decrease of 0.016 from .51 which is actually .494

  23. freckles
    • one year ago
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    so you have two points (0,.51) (1,.494)

  24. freckles
    • one year ago
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    you could even do more points if you wanted to

  25. freckles
    • one year ago
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    the 2nd year you would have another decrease of 0.016 so (2,.51-2(0.016)) or you could do it from the previous year (2,.494-.016) same number for y whatever strikes your fancy the cool think about recognizing it is (2,.51-2(0.016)) is that you have already noticed your line

  26. freckles
    • one year ago
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    for example if you have noticed for the 2nd your the y-coordinate was .51-2(0.016) then you might notice for xth year you have .51-x(0.016)

  27. freckles
    • one year ago
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    (x,.51-x(0.016)) which tells you the line is y=.51-x(0.016) or if you prefer to write as y=-0.016x+.51

  28. freckles
    • one year ago
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    the question gave you the y-intercept which was the initial percentage and it also gave you the rate you just needed to plug the numbers in

  29. Destinyyyy
    • one year ago
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    Okay. So the answer is p(x)= -0.016x +.51

  30. freckles
    • one year ago
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    yes

  31. Destinyyyy
    • one year ago
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    Okay thanks.

  32. freckles
    • one year ago
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    np I hope it makes sense though.. if you don't like those ugly decimal numbers it might be easier first to look at this example: Say we pick a year and call it t=0. And we are given at t=0 we have 1001 dogs. And we are also given we gain 5 dogs per year. Then for t=1 we have how many dogs?

  33. Destinyyyy
    • one year ago
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    I understand it now.

  34. freckles
    • one year ago
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    ok cool for my example the slope would be positive since we are gaining dogs and not losing dogs :) I didn't want to pick a sad example

  35. freckles
    • one year ago
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    if you wanted to know for my example the answer to my question would be 1001+5 or 1006 and if you wanted the equation of the line then it would be y=5x+1001 where y represents the number of dogs and x presents the years after whatever year t=0 represented

  36. Destinyyyy
    • one year ago
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    Alright. Thank you. Sorry this was my second to last question and I just want to be done. I've been up since 7.

  37. Destinyyyy
    • one year ago
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    The answer was incorrect. The correct answer is -1.6x+51

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