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anonymous
 one year ago
The area of a rectangle is
28 m2
, and the length of the rectangle is
1 m
more than double the width. Find the dimensions of the rectangle.
anonymous
 one year ago
The area of a rectangle is 28 m2 , and the length of the rectangle is 1 m more than double the width. Find the dimensions of the rectangle.

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Abhisar
 one year ago
Best ResponseYou've already chosen the best response.0Let the breadth be x then length will be (2x+1). Area of rectangle = length x Breadth => x(2x+1) = 28 Solve for x and find the length and breadth

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i tried doing that but i kept on getting the answer wrong

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.0Can you show me your work so that I could correct you

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sure how do i upload a picture

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.0Use the attach file below

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it is not letting me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nevermore i'll just get this one wrong

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.0Wait, You will get an equation \(\sf 2x^2 +x28 = 0\)

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.0Now, you need to solve this quadratic equation. You will get two values for x, one positive and one negative.

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.0Yes, You can use this website to check your value of x http://www.math.com/students/calculators/source/quadratic.htm

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.0Note: You need to pick the positive value. The value of x will be your breadth and the length will be 2x+1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok I think i understand I'm going to try to do it :)
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