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anonymous

  • one year ago

Precalc Logarithm help?

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  1. anonymous
    • one year ago
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    i'll help you

  2. anonymous
    • one year ago
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    Evaluate each of the following

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  3. anonymous
    • one year ago
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    @amistre64 @sammietaygreen @zepdrix

  4. sweetburger
    • one year ago
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    these all use the properties of logarithms do you know what these are?

  5. anonymous
    • one year ago
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    I honestly don't understand the first thing about logarithms

  6. anonymous
    • one year ago
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    @sweetburger

  7. freckles
    • one year ago
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    \[\ln(\frac{a}{b})=\ln(a)-\ln(b) \text{ Try applying the quotient rule \to the first one } \\ \]

  8. anonymous
    • one year ago
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    1-e^5? I don't think I understand....

  9. anonymous
    • one year ago
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    which one you stuck on?

  10. anonymous
    • one year ago
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    they are all the same really they are all using the same two facts \[\huge \log_b(b^x)=x\] and \[\huge b^{\log_b(x)}=x\] because the log is the inverse of the exponential

  11. anonymous
    • one year ago
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    for the first one \[\ln(\frac{1}{e^5})\] rewrite as \[\ln(e^{-5})\] then use the fact that \[\ln(x)=\log_e(x)\] so you have \[\log_e(e^{-5})=-5\]

  12. anonymous
    • one year ago
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    second one is even easier \[\large 10^{\log_{10}(\text{whatever})}=\text{whatever}\]

  13. anonymous
    • one year ago
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    third one is similar the bases are the same so \[\log_{2015}(2015^{-1})=?\]

  14. anonymous
    • one year ago
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    all of these, once written in exponential form, are kind of like "who's buried in grant's tomb"? what power would you raise 2015 to in order to get \(2015^{-1}\)? i guess \(-1\)

  15. freckles
    • one year ago
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    also applying the quotient rule to the first one looks like this: \[\ln(\frac{1}{e^5})=\ln(1)-\ln(e^5) \\ \text{ then use that } \ln(1)=0 \\ \text{ so } \ln(\frac{1}{e^5})=-\ln(e^5) \\ \text{ but you could have gotten away from using that rule as } satellite \text{ said }\]

  16. freckles
    • one year ago
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    because you still have to use the inverse thingy

  17. anonymous
    • one year ago
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    and all this time i thought the quotient rule was from calculus...

  18. anonymous
    • one year ago
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    inverse thingy lol

  19. freckles
    • one year ago
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    they call a lot of things the quotient rule

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