+WILL GIVE MEDAL!+

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days represent by n variable so just plugin the numbers to find the correct answer
|dw:1443788222785:dw|
let's try 4th one|dw:1443788458435:dw| \[\huge\rm a_n=a_{n-1}+2(n+1)\] substitute n for 4 \[\large\rm a_\color{Red}{4}=a_{\color{ReD}{4}-1}+2(\color{reD}{4}+1)\] 4-1 = 3 so a_{4-1} =a_3 now substitute a_3 for 10 bec `after 3 days , there are 10 cells` is same as a_3 =10 \[a_4=10+2(5) ~~~~~~~~~~~~~~~~~~~~~~a_4=20\]but we should get 16 so D is wrong now try other 3
so a. the equation is a4=a4−1+2(4) ? Or a4 = 10 - 1 + 8 or 17?
it's \[\huge\rm a_{4-1}= a_3\]
Oh so a is 16 then??
{4-1} is base which is equal to a_3
\(\color{blue}{\text{Originally Posted by}}\) @rockinhood so a. the equation is a4=a4−1+2(4) ? Or a4 = 10 - 1 + 8 or 17? \(\color{blue}{\text{End of Quote}}\) a_{4-1}=a_3 so u wil get a_3 +8
now replace a_3 with its value
10_3 + 8
a_3 means 3rd term
it's not 10 with base 3
a_1= first term a_2 = 2nd term a_3= 3rd term so it's 10+8|dw:1443797343672:dw|
Oh ok
10+8 equal =18 so a isn't correct bec when we substitute 4 for n we should get 16
So now I have to check b? a_n = a_n - 1 + n^2
yep btw u can use 3rd and 2nd term :=) doesn't maatter
how did you get 9?
That was a mistake that I jsut realized lol
I just did C a_n = a_n - 1 + (n + 2) 10 + 6 Is it c?
yes right 10+6 =16!
a_n - 1 + (n + 2) a_3 + (4 + 2) 10 + 6
Yes! Thanks for the help, I'll be sure to let you know if I need help with any others :D
alright good work!

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