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Broskishelleh

  • one year ago

A sandbag was thrown downward from a building. The function f(t) = -16t2 - 64t + 80 shows the height f(t), in feet, of the sandbag after t seconds: Part A: Factor the function f(t) and use the factors to interpret the meaning of the x-intercept of the function. (4 points) Part B: Complete the square of the expression for f(x) to determine the vertex of the graph of f(x). Would this be a maximum or minimum on the graph? (4 points) Part C: Use your answer in part B to determine the axis of symmetry for f(x)? (2 points)

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  1. Broskishelleh
    • one year ago
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    Please halp

  2. Nnesha
    • one year ago
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    given expression is f(t) where is f(x) or is it a typo ?

  3. Broskishelleh
    • one year ago
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    F(t) is F(x), just replace t with x if you want

  4. Nnesha
    • one year ago
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    alright let's factor the right side i have few mints sorry

  5. Broskishelleh
    • one year ago
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    It's fine

  6. Nnesha
    • one year ago
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    \[\huge\rm f(t)= \color{ReD}{-16t^2-64t+80}\] first take out the common factor

  7. Broskishelleh
    • one year ago
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    The common factor is 8

  8. Nnesha
    • one year ago
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    well we need GREATEST common factor

  9. Broskishelleh
    • one year ago
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    Oh, 16 then my mistake

  10. Nnesha
    • one year ago
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    yes right and bec leading coefficient is negative we can take out the negative 16

  11. Nnesha
    • one year ago
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    and sorry gtg :(

  12. Broskishelleh
    • one year ago
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    Alright that leaves us with \[f(t) = -4 + 5\]

  13. Broskishelleh
    • one year ago
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    Okay bye

  14. Nnesha
    • one year ago
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    aw didn't get the help :( sorry

  15. Nnesha
    • one year ago
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    alright when we find the common denominator we should divide all terms by the common factor \[\large\rm \color{blue}{\frac{ -16t^2 }{ -16 }-\frac{ 64t }{ -16}+\frac{ 80 }{ -16} }\]\[\large \rm f(t)=-16(\color{blue}{t^2+4t-5})\] now factor t^2+4t-5 there are more than 3 ways to factor o the quadratic equation you can use AC method(easy) find two number when you multiply them you should get product of AC (a=leading coefficient , c=constant term) and when you add or subtract them you should get middle term(b)

  16. Nnesha
    • one year ago
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    remember t^2 is same as 1t^2 so in this question leading coefficient is 1

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