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Please halp

given expression is f(t) where is f(x) or is it a typo ?

F(t) is F(x), just replace t with x if you want

alright let's factor the right side
i have few mints sorry

It's fine

\[\huge\rm f(t)= \color{ReD}{-16t^2-64t+80}\]
first take out the common factor

The common factor is 8

well we need GREATEST common factor

Oh, 16 then my mistake

yes right and bec leading coefficient is negative we can take out the negative 16

and sorry gtg :(

Alright that leaves us with \[f(t) = -4 + 5\]

Okay bye

aw didn't get the help :(
sorry

remember t^2 is same as 1t^2 so in this question leading coefficient is 1