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Pulsified333

  • one year ago

Assume that Pr[E]=17/30, Pr[F|E]=12/17, and Pr[E′∩F′]=1/5. (1) Pr[F]=

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  1. Pulsified333
    • one year ago
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    I know that Pr[E ∩ F] = 102/255

  2. Pulsified333
    • one year ago
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    @Jhannybean do you know how to do this?

  3. amistre64
    • one year ago
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    |dw:1443879084099:dw|

  4. amistre64
    • one year ago
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    E = 17 out of 30, to let E=17 and U=30 F|E (the amount of F that is contained in E) is 12 out of 17 the set E'nF' might be hard to imagine, but it is just the elements that are neither in E nor in F ... 1 out of 5, or since U = 30, 6 out of 30 |dw:1443879301341:dw|

  5. amistre64
    • one year ago
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    since U = 30, then 5+12+6+X = 30 to fill in the missing part of F therefore F will equal (12+x) out of 30

  6. amistre64
    • one year ago
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    12+x = 30-11=20-1=19

  7. amistre64
    • one year ago
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    |dw:1443879474433:dw|

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