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Pulsified333
 one year ago
Assume that Pr[E]=17/30, Pr[FE]=12/17, and Pr[E′∩F′]=1/5.
(1) Pr[F]=
Pulsified333
 one year ago
Assume that Pr[E]=17/30, Pr[FE]=12/17, and Pr[E′∩F′]=1/5. (1) Pr[F]=

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Pulsified333
 one year ago
Best ResponseYou've already chosen the best response.0I know that Pr[E ∩ F] = 102/255

Pulsified333
 one year ago
Best ResponseYou've already chosen the best response.0@Jhannybean do you know how to do this?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443879084099:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0E = 17 out of 30, to let E=17 and U=30 FE (the amount of F that is contained in E) is 12 out of 17 the set E'nF' might be hard to imagine, but it is just the elements that are neither in E nor in F ... 1 out of 5, or since U = 30, 6 out of 30 dw:1443879301341:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0since U = 30, then 5+12+6+X = 30 to fill in the missing part of F therefore F will equal (12+x) out of 30

amistre64
 one year ago
Best ResponseYou've already chosen the best response.012+x = 3011=201=19

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443879474433:dw
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