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lisa123

  • one year ago

Write equations of the lines through the given point parallel to and perpendicular to the given line. 6x − 2y = 9, (3, 1)

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  1. anonymous
    • one year ago
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    ok find a slope from this line and since the parallel slope has identical slope , u can use that to get an equation by using

  2. anonymous
    • one year ago
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    \[y-y _{1}=m(x-x _{1})\]

  3. anonymous
    • one year ago
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    do u know hoe to find a slope from an equation , you make y the subject like (y=...)

  4. anonymous
    • one year ago
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    how*

  5. lisa123
    • one year ago
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    I think I did this but I got it wrong 6x-2y=9 -2y=-6x+9 y=3x-9/2 y-1=3(x-3) y=3x-8:parallel line

  6. anonymous
    • one year ago
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    well done u are right :)

  7. lisa123
    • one year ago
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    No, the answer is wrong...according to my hw website

  8. anonymous
    • one year ago
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    yea i realized u didnt do the third step right

  9. lisa123
    • one year ago
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    oh what is that?

  10. anonymous
    • one year ago
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    no ur right the book is wrong

  11. anonymous
    • one year ago
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    i thought u maybe messed up while making the y subject its right

  12. lisa123
    • one year ago
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    i also got y=-1/3x for the perpendicular line but it tells me thats wrong too

  13. anonymous
    • one year ago
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    nope ur right

  14. lisa123
    • one year ago
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    Hmm okay I'll show my teacher. Thanks!

  15. anonymous
    • one year ago
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    i am 110% ur right

  16. anonymous
    • one year ago
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    no worries happy to help

  17. lisa123
    • one year ago
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    Can you help me with another problem

  18. anonymous
    • one year ago
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    yea sure

  19. lisa123
    • one year ago
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    Find the x- and y-intercepts of the graph of the equation. y = x4 − 25

  20. lisa123
    • one year ago
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    x - intercept( larger value): sqrt 5,0 y-intercept : 0,-25 x- intercept (smaller value) ??

  21. anonymous
    • one year ago
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    is the eq \[x ^{4}-25\]

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