Write equations of the lines through the given point parallel to and perpendicular to the given line. 6x − 2y = 9, (3, 1)

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Write equations of the lines through the given point parallel to and perpendicular to the given line. 6x − 2y = 9, (3, 1)

Mathematics
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ok find a slope from this line and since the parallel slope has identical slope , u can use that to get an equation by using
\[y-y _{1}=m(x-x _{1})\]
do u know hoe to find a slope from an equation , you make y the subject like (y=...)

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I think I did this but I got it wrong 6x-2y=9 -2y=-6x+9 y=3x-9/2 y-1=3(x-3) y=3x-8:parallel line
well done u are right :)
No, the answer is wrong...according to my hw website
yea i realized u didnt do the third step right
oh what is that?
no ur right the book is wrong
i thought u maybe messed up while making the y subject its right
i also got y=-1/3x for the perpendicular line but it tells me thats wrong too
nope ur right
Hmm okay I'll show my teacher. Thanks!
i am 110% ur right
no worries happy to help
Can you help me with another problem
yea sure
Find the x- and y-intercepts of the graph of the equation. y = x4 − 25
x - intercept( larger value): sqrt 5,0 y-intercept : 0,-25 x- intercept (smaller value) ??
is the eq \[x ^{4}-25\]

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