anonymous
  • anonymous
Predict the distance at which two cars will collide when they start at opposite ends separated by a distance of 4 meters. One car leaves 1.5 seconds after the first car is released. One car has a velocity of 0.38 m/s and the other has a velocity of 0.31 m/s.
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Try = 2aS=Vf^2-Vi^2
anonymous
  • anonymous
Vf=vi+at for a
anonymous
  • anonymous
what am i plugging in?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Take vi=0 and put the value now you have got vf for both cars..put the velocity for the car which started 1.5 sec before and find the distance..
anonymous
  • anonymous
You can get acceleration from vf=vi+at..then find S..where S is distance...

Looking for something else?

Not the answer you are looking for? Search for more explanations.