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anonymous

  • one year ago

medal Complete the general form of the equation of a sinusoidal function having an amplitude of 6, a period of 2pie/3 , and a phase shift to the left 1 unit. y =

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  1. chrisplusian
    • one year ago
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    \[6\sin(\frac{ 2\pi }{ 3 }+1)\]

  2. chrisplusian
    • one year ago
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    \[6\sin(\frac{ 2\pi }{ 3 }x+1)\]

  3. anonymous
    • one year ago
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    thx

  4. chrisplusian
    • one year ago
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    It can be x that is attached to the 2pi/3 or a t or whatever parameter you use

  5. baru
    • one year ago
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    2pi/3 is the period, you have to change it to "frequency"

  6. chrisplusian
    • one year ago
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    Do you understand why? Or did you just need to check your answer?

  7. anonymous
    • one year ago
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    no

  8. chrisplusian
    • one year ago
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    It depends on what context.... the trig books show this as "angular frequency" in radians per second. If you want frequency in Hz for an engineering class then you would need to convert this into Hz

  9. anonymous
    • one year ago
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    i dont have a book

  10. baru
    • one year ago
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    they given value 2pi/3 is "time period". angular frequence = 2pi/(time period) so angular frequency is "3"

  11. baru
    • one year ago
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    y=6sin(3(x+1))

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