## anonymous one year ago A man release a stone at the top edge of a tower. During the last second of its travel,the stone fall through a distance of(9/25)H,where H is the tower’s height .Find H

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1. IrishBoy123

|dw:1443817879110:dw| equations of motion (EoM) use EoM $$v^2 = u^2 + 2ax$$ to establish velocities at positions shown in blue in drawing from EoM $$v = u + at$$ for final 1 second of flight time, we can say $$v = u + g(1)$$ $$\sqrt{2gH} = \sqrt{2g \frac{16}{25}H} + g$$ then, solve for H [in terms of g]