## anonymous one year ago You are given a metal sample of weight 28.4 and asked to determine its specific heat. You add 1.25 x 104 J of heat to the sample and then measure a temperature increase of 18.0°C. What is the specific heat of the sample? helpppp please

$Q=mC \Delta T$ where Q is the amount of heat added to an object, m is the mass of the object in kg, C is the specific heat of the object's constituent material, and $\Delta T$ is the change in temperature observed (in Kelvin or Celsius degrees) Solving for the specific heat yields: $C=\frac{ Q }{ m \Delta T }$ Plug in your given values on the right hand side of the above equation. Check your units!