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Micheal1234
 one year ago
1.is (0,3) a solution to the equation y=x+3?
yes or no
2.is (1,4) a solution to the equation y=2x
yes or no
3.Look at the following points.
(4,0), (3,1), (6,3), (2,4)
Which are solutions to y=x4? choose all correct answers there are two correct answers.
A. (6,3) B. (is (4,0) C. (3,1) D. (2,4)
4.There are 8 crackers in 1 serving, 16 crackers in 2 servings, 24 crackers in 3 servings, and so on. How many crackers are in a box of 12 servings?
A.80
B.96
C.108
D.120
Micheal1234
 one year ago
1.is (0,3) a solution to the equation y=x+3? yes or no 2.is (1,4) a solution to the equation y=2x yes or no 3.Look at the following points. (4,0), (3,1), (6,3), (2,4) Which are solutions to y=x4? choose all correct answers there are two correct answers. A. (6,3) B. (is (4,0) C. (3,1) D. (2,4) 4.There are 8 crackers in 1 serving, 16 crackers in 2 servings, 24 crackers in 3 servings, and so on. How many crackers are in a box of 12 servings? A.80 B.96 C.108 D.120

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0to complete the problems 1 and 2, just substitute the first number in brackets into x and second into y. Solve and check if it is true or not.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the same is for 3rd problem. Substitute instead of x and y each pair of numbers.

Micheal1234
 one year ago
Best ResponseYou've already chosen the best response.0what do you mean i am not good with big words

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01. you have equation y=x+3. You have 0 for x and 3 for y. Substitute: 3 = 0 + 3 This is true.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so (0, 3) is solution to equation y=x+3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do the same thing with 2nd.
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