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Micheal1234

  • one year ago

1.is (0,3) a solution to the equation y=x+3? yes or no 2.is (1,-4) a solution to the equation y=-2x yes or no 3.Look at the following points. (4,0), (3,-1), (6,3), (2,4) Which are solutions to y=x-4? choose all correct answers there are two correct answers. A. (6,3) B. (is (4,0) C. (3,-1) D. (2,-4) 4.There are 8 crackers in 1 serving, 16 crackers in 2 servings, 24 crackers in 3 servings, and so on. How many crackers are in a box of 12 servings? A.80 B.96 C.108 D.120

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  1. anonymous
    • one year ago
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    to complete the problems 1 and 2, just substitute the first number in brackets into x and second into y. Solve and check if it is true or not.

  2. anonymous
    • one year ago
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    the same is for 3rd problem. Substitute instead of x and y each pair of numbers.

  3. Micheal1234
    • one year ago
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    what do you mean i am not good with big words

  4. anonymous
    • one year ago
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    1. you have equation y=x+3. You have 0 for x and 3 for y. Substitute: 3 = 0 + 3 This is true.

  5. anonymous
    • one year ago
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    so (0, 3) is solution to equation y=x+3

  6. anonymous
    • one year ago
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    do the same thing with 2nd.

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