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- Micheal1234

1.is (0,3) a solution to the equation y=x+3?
yes or no
2.is (1,-4) a solution to the equation y=-2x
yes or no
3.Look at the following points.
(4,0), (3,-1), (6,3), (2,4)
Which are solutions to y=x-4? choose all correct answers there are two correct answers.
A. (6,3) B. (is (4,0) C. (3,-1) D. (2,-4)
4.There are 8 crackers in 1 serving, 16 crackers in 2 servings, 24 crackers in 3 servings, and so on. How many crackers are in a box of 12 servings?
A.80
B.96
C.108
D.120

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- Micheal1234

- katieb

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- anonymous

to complete the problems 1 and 2, just substitute the first number in brackets into x and second into y. Solve and check if it is true or not.

- anonymous

the same is for 3rd problem. Substitute instead of x and y each pair of numbers.

- Micheal1234

what do you mean i am not good with big words

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- anonymous

1. you have equation y=x+3. You have 0 for x and 3 for y.
Substitute:
3 = 0 + 3
This is true.

- anonymous

so (0, 3) is solution to equation y=x+3

- anonymous

do the same thing with 2nd.

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