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anonymous

  • one year ago

Factor

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  1. anonymous
    • one year ago
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    \[14x^2y^3+42xy+7x^2y^2+21x\]

  2. Nnesha
    • one year ago
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    make a group of 2 terms |dw:1443793326901:dw| now take out the common factor of first two and last two terms

  3. anonymous
    • one year ago
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    There is a GCF though, so don't you factor that out first 7x(2xy^3+xy^2+7y+3)

  4. Nnesha
    • one year ago
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    find GCF( GREATEST common factor)

  5. anonymous
    • one year ago
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    Yeah 7x is the GCF

  6. Nnesha
    • one year ago
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    that's right u will get the same answer now apply factor by grouping method for (2xy^3+xy^2+7y+3)

  7. anonymous
    • one year ago
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    You can't group 3 with anything though

  8. Nnesha
    • one year ago
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    there are 4 terms with no GCF

  9. Nnesha
    • one year ago
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    |dw:1443793724019:dw|

  10. anonymous
    • one year ago
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    7y and 3 have no common factor though

  11. Nnesha
    • one year ago
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    wait a sec brb

  12. baru
    • one year ago
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    its 6y not 7y

  13. anonymous
    • one year ago
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    no it's 7y

  14. anonymous
    • one year ago
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    wait

  15. baru
    • one year ago
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    7*7=49

  16. anonymous
    • one year ago
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    listen i have dyscalculia, dumb mistake ik

  17. Nnesha
    • one year ago
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    ahh |dw:1443793944611:dw|

  18. Nnesha
    • one year ago
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    in other words what would you get when you take out 7x from 42xy ?

  19. anonymous
    • one year ago
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    so i have 7x(xy^2+3)(2y+1)

  20. Nnesha
    • one year ago
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    yes right we should divide all 4 terms by common factor |dw:1443794085081:dw| 42xy^2 divide by 7x = 6y