Factor

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\[14x^2y^3+42xy+7x^2y^2+21x\]
make a group of 2 terms |dw:1443793326901:dw| now take out the common factor of first two and last two terms
There is a GCF though, so don't you factor that out first 7x(2xy^3+xy^2+7y+3)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

find GCF( GREATEST common factor)
Yeah 7x is the GCF
that's right u will get the same answer now apply factor by grouping method for (2xy^3+xy^2+7y+3)
You can't group 3 with anything though
there are 4 terms with no GCF
|dw:1443793724019:dw|
7y and 3 have no common factor though
wait a sec brb
its 6y not 7y
no it's 7y
wait
7*7=49
listen i have dyscalculia, dumb mistake ik
ahh |dw:1443793944611:dw|
in other words what would you get when you take out 7x from 42xy ?
so i have 7x(xy^2+3)(2y+1)
yes right we should divide all 4 terms by common factor |dw:1443794085081:dw| 42xy^2 divide by 7x = 6y