anonymous
  • anonymous
Factor
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[14x^2y^3+42xy+7x^2y^2+21x\]
Nnesha
  • Nnesha
make a group of 2 terms |dw:1443793326901:dw| now take out the common factor of first two and last two terms
anonymous
  • anonymous
There is a GCF though, so don't you factor that out first 7x(2xy^3+xy^2+7y+3)

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Nnesha
  • Nnesha
find GCF( GREATEST common factor)
anonymous
  • anonymous
Yeah 7x is the GCF
Nnesha
  • Nnesha
that's right u will get the same answer now apply factor by grouping method for (2xy^3+xy^2+7y+3)
anonymous
  • anonymous
You can't group 3 with anything though
Nnesha
  • Nnesha
there are 4 terms with no GCF
Nnesha
  • Nnesha
|dw:1443793724019:dw|
anonymous
  • anonymous
7y and 3 have no common factor though
Nnesha
  • Nnesha
wait a sec brb
baru
  • baru
its 6y not 7y
anonymous
  • anonymous
no it's 7y
anonymous
  • anonymous
wait
baru
  • baru
7*7=49
anonymous
  • anonymous
listen i have dyscalculia, dumb mistake ik
Nnesha
  • Nnesha
ahh |dw:1443793944611:dw|
Nnesha
  • Nnesha
in other words what would you get when you take out 7x from 42xy ?
anonymous
  • anonymous
so i have 7x(xy^2+3)(2y+1)
Nnesha
  • Nnesha
yes right we should divide all 4 terms by common factor |dw:1443794085081:dw| 42xy^2 divide by 7x = 6y